a) Find the total current flowing through that portion of the spherical surface r = 0.8, bounded by 0.17 <0 <0.37, 0 < < 2: This will be = SfJ₁n|₂da = .3πT 1 = 346.5 1 = - .3 400 sin 0 (.8)² +4 cos(20)] de = 77.4 A 2T .17 -(.8)² sin 0 de do= b) Find the average value of J over the defined area. The area is с2л с.Зл 400(.8)²2π .3π 4.64 S .17 sin² de

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electromagnetic field)I want a detailed solution because my teacher changes the numbers. I want a detailed solution. Understand the solution
Example
1 = √ √ J⋅ 1 | ₁
J.n
S
= 346.5
a) Find the total current flowing through that portion of the spherical surface r = 0.8, bounded by
0.1л <0 <0.37, 0 << 27: This will be
da =
J =
400 sin 0
²+4
2π .3 400 sin 0
Sot (18)² + 4)
.17
.3π
S [1 − cos(20)] de
.1л
Area =
a, A/m²
-(.8)² sin 0 de do=
= 77.4 A
b) Find the average value of J over the defined area. The area is
.2т
.3π
= 1²th 27 (8)² sine de do
=
.17
The average current density is thus Javg
400(.8)²2π ..37
4.64
1.46 m²
(77.4/1.46) ar = 53.0 a, A/m².
.17
de
Transcribed Image Text:Example 1 = √ √ J⋅ 1 | ₁ J.n S = 346.5 a) Find the total current flowing through that portion of the spherical surface r = 0.8, bounded by 0.1л <0 <0.37, 0 << 27: This will be da = J = 400 sin 0 ²+4 2π .3 400 sin 0 Sot (18)² + 4) .17 .3π S [1 − cos(20)] de .1л Area = a, A/m² -(.8)² sin 0 de do= = 77.4 A b) Find the average value of J over the defined area. The area is .2т .3π = 1²th 27 (8)² sine de do = .17 The average current density is thus Javg 400(.8)²2π ..37 4.64 1.46 m² (77.4/1.46) ar = 53.0 a, A/m². .17 de
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