a) Find right side tail for t = 2.447 and sample size 7 b) Find level of confidence interval for t = 2.447 and sample size 7 c) Find level of confidence interval for t = 1.725, sample size 21
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a) Find right side tail for t = 2.447 and
b) Find level of confidence interval for t = 2.447 and sample size 7
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- A government agency is interested in coyote weights. They take a SRS of 34 coyotes from western states and find that they have a mean weight of 12.4 kilograms (kg) with a standard deviation of 2.1 kg. They also take a random sample of 41 coyotes from eastern states andfind they have a. mean weight of 13.6 kilograms (kg) with a standard deviation of 2.3 kg. Givela 80% confidence interval for the average extra amount that eastern coyotes weigh. Provide a 1-2 sentence explanation of what your results mean in addition to appropriately stating your results in a complete sentence.For a random sample of 50 measurements on the breaking strength of cotton threads, the mean breaking strength was found to be 210 grams and the standard deviation 18 grams. Calculate a 90% confidence interval for the true mean breaking strength of cotton threads of this type.In a sample of 10 randomly selected black bears from northeast Pennsylvania, the sample mean was 214.1 pounds and the sample standard deviation was 51.1 pounds. Construct a 99% confidence interval estimate for the population standard deviation of all black bears in this region.
- Create a 90% confidence interval for a population mean from a sample of size 19 with sample mean I = 6.9 and sample standard deviation S = 2. [three decimal accuracy] [three decimal accuracy]Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoccupied seats per flight over the past year. To accomplish this, the records of 250 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 11.3 seats and the sample standard deviation is 4.5 seats. Construct a 92% confidence interval for the population mean number of unoccupied seats per flight. State the confidence interval. (Round your answers to two decimal places.) а. b. Calculate the error bound. (Round your answer to two decimal places.)The Aloha Taxi Cab Company of Honolulu, Hawaii, wants to estimate the mean life of tires on its cabs. A random sample of 15 tires from the cabs are found to have a life of 18,280 miles with sample standard deviation of 1,310 miles. Find a 90% confidence interval for the mean life of all such tires on Aloha Taxi Cabs.
- A company that manufactures baseball bats believes that its new bat will allow players to hit the ball 30 feet farther than its current model. The owner hires a professional baseball player known for hitting home runs to hit ten balls with each bat and he measures the distance each ball is hit to test the company's claim. The results of the batting experiment are shown in the following table. Construct a 90 % confidence interval for the true difference between the mean distance hit with the new model and the mean distance hit with the older model. Assume that the variances of the two populations are the same. Let Population 1 be the distances of balls hit with the new model baseball bat and Population 2 be the distances of balls hit with the old model. Round the endpoints of the interval to one decimal place, if necessary. Hitting Distance (in Feet) New Model 246 240 272 262 237 250 247 235 261 216 Old Model 293 232 299 279 239 228 256 292 272 298Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its mean number of unoccupied seats per flight over the past year. To accomplish this, the records of 225 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 11.6 seats and the sample standard deviation is 4.1 seats. Construct a 92% confidence interval for the population mean number of unoccupied seats per flight. (Round your answers to one decimal place.) margin of error E = Lower limit = Upper limit =Group Number of Children Mean PEF Std Dev PEF Chronic Bronchitis 25 281 68 No Chronic Bronchitis 25 319 74 Using the data presented above: a) Construct a 95% confidence interval for the mean PEF in children without chronic bronchitis b) Determine how many children would be required to ensure that the margin of error in (a) does not exceed 10 units.
