In question 2 a 90% confidence interval was computed based on a sample of 250 adults. If the level were increased to 99%. what impact would this have on the margin of error and width of the confidence interval? A) The margin of error would increase and the width would decrease. B) The margin of error would decrease and the width would increase. C) Neither the margin of error nor the width would be affected. D) Both the margin of error and the width would increase. E) Both the margin of error and the width would decrease.
In question 2 a 90% confidence interval was computed based on a sample of 250 adults. If the level were increased to 99%. what impact would this have on the margin of error and width of the confidence interval? A) The margin of error would increase and the width would decrease. B) The margin of error would decrease and the width would increase. C) Neither the margin of error nor the width would be affected. D) Both the margin of error and the width would increase. E) Both the margin of error and the width would decrease.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:In question 2, a 90% confidence interval was computed based on a sample of 250 adults. If the confidence level were increased to 99%, what impact would this have on the margin of error and width of the confidence interval?
(A) The margin of error would increase and the width would decrease.
(B) The margin of error would decrease and the width would increase.
(C) Neither the margin of error nor the width would be affected.
(D) Both the margin of error and the width would increase.
(E) Both the margin of error and the width would decrease.

Transcribed Image Text:A simple random sample of 250 adults from the Commonwealth of Virginia was selected, and the distance each must travel to visit their primary care physician was recorded. The mean distance for this sample of 250 adults was 14.6 miles, with a standard deviation of 6.9 miles, and the distribution is skewed to the right. If appropriate, use this information to calculate and interpret a 90% confidence interval for the mean distance that all adults in the Commonwealth of Virginia must travel to visit their primary care physician.
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