QUESTION 7A field is to be surveyed for pesticide residues. Other fields treated in similar ways have been shown to have residues of 40–200ug/g, with a standard deviation of about 30 ug/g. If an error level of + 3 ug/g is acceptable, how many samples are needed to be 95%confident that the requirement is met?enevaFor the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).BIUSParagraphArial10ptAiroon,x² X2 San+,ABCierg田用田EXErene<> Ť {}ImeREAulti!!!田

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Answered: A field is to be surveyed for pesticide…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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When samples of size 30 are collected from a normal population that has a mean of 200 and a standard deviation of 40, the standard deviation of the sampling distribution is?
The daily sleep duration among college students is normally distributed with a mean of 8.13 and standard deviation of 1.87. You want to use a sample size such that 95% of the averages fall within ±15±15 minutes (.25 of an hour) of the true mean of 8.13. Determine the smallest number of students you need to sample.
Suppose that the volume of sound generated by heavy machinery in a factory is normally distributed, with a mean of 50 dB and a standard deviation of 10 dB. If measurements are taken twice an hour during an eight hour period, 20% of the sample average sound volumes will be above what value?"
It takes an average of 14.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 65 injured patients to immediately tell the truth about the injury and noticed that they averaged 15.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.05 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly greater than 14.5 at αα = 0.05, so there is statistically significant…
It takes an average of 10.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 46 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.98 minutes. What can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: Please provide number H0:H0: mean =Correct __?__ H1:H1: mean > Correct_ __?__ The test statistic t = __?__ (please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.)
claim the standard deviation of pulse rates in adult women is at least 50. for a random sample of adult females the pulse rates have a standard deviation of 11.6.
While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 1.50 m and 5.50 m. What is the standard deviation of the water depth?
A series of measurements in the lab led to an experimental result of 32.9 mL, with a calculated standard deviation of 0.3 mL. What is the standard way to report this result? Select one: 32.6-33.2 mL 32.9 ± 0.3 mL 32.9 ± 0.30 mL = 32.9 mL
Suppose a certain dog breed has an average weight of 22.72 with a standard deviation of 4.30. What is the z-score of a dog whose length is 37.27? Answers should be correct to two decimal places.
An Internet provider has analyzed the amount of time it’s customers are online per session. It found that the distribution of connect times has a mean a 43 minutes and a standard deviation of 10 minutes. For this distribution find the raw score that corresponds to a z score of 1.1
It takes an average of 14 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 43 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.5 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.1 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 14 at αα = 0.01, so there is statistically significant…
It takes an average of 12.7 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 51 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.77 minutes. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer > < ≠ = H1:H1: ? p μ Select an answer = < ≠ > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject…

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