A double-slit experiment has slit spacing 0.12 mm and the slit-to-screen distance L of 95 cm, if the slits are illuminated with 480-nm laser light, what will be the fringe spacing ?

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A double-slit experiment has slit spacing 0.12 mm and the slit-to-screen distance L of 95 cm, if the slits are illuminated
with 480-nm laser light, what will be the fringe spacing ?
Transcribed Image Text:A double-slit experiment has slit spacing 0.12 mm and the slit-to-screen distance L of 95 cm, if the slits are illuminated with 480-nm laser light, what will be the fringe spacing ?
Expert Solution
Concept and Principle:
  • When light from two sources meets interference takes place. In the double slit experiment, this is achieved by using two closely spaced slits. The two waves coming from the slits will interfere creating alternating dark and bright fringes with central maxima.

 

  • The bright fringes are formed due to constructive interference and dark fringes are formed due to destructive interference.

 

  • The distance to a bright fringe from the central maximum caused by constructive interference is given by,

ybright=mλLd

Here m is the order of the maxima, λ is the wavelength of the source, L is the distance from the slit to the screen's center point, and d is the slit spacing.

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