A digital binary communication system with data rate 110 bits/sec and AWGN psdNo= 0.01 uses the following signals to represent binary digits 1 and 0,respectively:Osts 1/110Osts 1/110s1(t) = 1.7,So(t) = - 25,(t),Find the threshold, employed at the receiver, which minimizes the average probability oferror of the optimum receiver assuming the two transmitted signals are equallyprobable.The answer should be a number rounded to 5 decimal digits (the minus sign isaccepted while other symbols like % are not)Find the average energy per signal assuming that the two signals are equally probable.

A digital binary communication system with data rate 110 bits/sec and AWGN p No= 0.01 uses the following signals to represent binary digits 1 and 0, respectively: s1(t) = 1.7, Osts 1/110 So(t) = - 2s,(t), Osts 1/110 Find the threshold, employed at the receiver, which minimizes the average probability error of the optimum receiver assuming the two transmitted signals are equally probable. The answer should be a number rounded to 5 decimal digits (the minus sign is accepted while other symbols like % are not)

A digital binary communication system with data rate 110 bits/sec and AWGN p No= 0.01 uses the following signals to represent binary digits 1 and 0, respectively: s1(t) = 1.7, Osts 1/110 So(t) = - 2s,(t), Osts 1/110 Find the threshold, employed at the receiver, which minimizes the average probability error of the optimum receiver assuming the two transmitted signals are equally probable. The answer should be a number rounded to 5 decimal digits (the minus sign is accepted while other symbols like % are not)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Eight input signals, each of bandwidth 4 kHz are timely multiplexed, quantized and binary PCM coded. The error in amplitude level of quantization process must be greater that 0.00001 of squared of peak amplitude. Find the values of M, N and bit rate if the sampling rate considered as 50% above the Nyquist rate. * 1 M=183 levels, N=8 bits, rb= 768 kbps 2 M=122 levels, N=7 bits, rb= 768 kbps 3 M=222 levels, N=8 bits, rb= 1068 kbps 4 M=162 levels, N=6 bits, rb= 468 kbps 5 M=192 levels, N=8 bits, rb= 868 kbps 6 M=102 levels, N=7 bits, rb= 868 kbps 7 M=202 levels, N=8 bits, rb= 968 kbps
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N=14 pls answer asap!!
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These multiple choice question from DIGITAL COMMUNICATIONS course.just write for me the final answer. 10) A broadcast TV channel has a bandwidth of 6 MHz Assume that the sampling rate is equal to the Nyquist rate, calculate the bit rate of PCM system using a 4-bit PCM code: a. 64 Mbps b. 24 Mbps c. 48 Mbps d. 12 Mbps