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(a) Determine the lower cutoff frequency for the network of Fig. 11.16 using the fol- lowing parameters: EXAMPLE 11.9 C, = 10 µF, CE = 20 µF, Cc =1 µF R, = 1 kN, RL = 2.2 kN R = 40 kN, R2 = 10 kn, Rg = 2 kn, Rc =4 kn, B = 100, ro = 0 N, Vcc = 20 V

(a) Determine the lower cutoff frequency for the network of Fig. 11.16 using the fol- lowing parameters: EXAMPLE 11.9 C, = 10 µF, CE = 20 µF, Cc =1 µF R, = 1 kN, RL = 2.2 kN R = 40 kN, R2 = 10 kn, Rg = 2 kn, Rc =4 kn, B = 100, ro = 0 N, Vcc = 20 V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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(a) Determine the lower cutoff frequency for the network of Fig. 11.16 using the fol- lowing parameters: EXAMPLE 11.9 C, = 10 µF, CE = 20 µF, Cc = 1 µF R, = 1 kn, RL = 2.2 kN R = 40 kn, R2 = 10 kn, Rg = 2 kn, Rc = 4 kN, B = 100, r, = 0 n, Vcc = 20 V
Transcribed Image Text:(a) Determine the lower cutoff frequency for the network of Fig. 11.16 using the fol- lowing parameters: EXAMPLE 11.9 C, = 10 µF, CE = 20 µF, Cc = 1 µF R, = 1 kn, RL = 2.2 kN R = 40 kn, R2 = 10 kn, Rg = 2 kn, Rc = 4 kN, B = 100, r, = 0 n, Vcc = 20 V
20.00V AC=ok VCC- 20v MAG=ok PHASE=ok RC 4k R1 40k CÇ 13.73V ov Rs Cs 3.875V Q1 Q2N2222 1uF 1k 10uF 3.166V RL3 2.2k Vs( 1mv R2 10k REE 2k CE20UF OV OV Figure 11.25 Network of Figure 11.16 with assigned values. 3.
Transcribed Image Text:20.00V AC=ok VCC- 20v MAG=ok PHASE=ok RC 4k R1 40k CÇ 13.73V ov Rs Cs 3.875V Q1 Q2N2222 1uF 1k 10uF 3.166V RL3 2.2k Vs( 1mv R2 10k REE 2k CE20UF OV OV Figure 11.25 Network of Figure 11.16 with assigned values. 3.
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