A dentist uses a curved mirror to view teeth on the upper side ofthe mouth. Suppose she wants an upright image with amagnification of 2.20 when the mirror is 1.10 cm from a tooth.(Treat this problem as though the object and image lie along astraight line.)For related problem-solving tips and strategies, you may want toview a Video Tutor Solution ofGraphical construction of an image from a mirror.What kind of mirror is needed? Use a ray diagram to decide, without performing any calculations.concaveconvexSubmitPrevious AnswersCorrect111Set Up: +/=/ and m =SSolve: s'Part B=sfs-fand m = -|f|= -f so m = +·Y17 ΑΣΦf, R=2.42,4.84=-.m = +2.20 and s = 1.10cm. An upright image must be virtual.For a concave mirror, m can be larger than 1.00. For a convex mirror,s-f|f|s+|f|and m is always less than 1.00. The mirror must be concave (f> 0).What must be the focal length and radius of curvature of this mirror?Enter your answer in centimeters separated by a comma.Submit Previous Answers Request AnswerX Incorrect; Try Again; 4 attempts remaining?cm

B) Write the expression for the magnification and substitute the corresponidng values to calculate…

A dentist uses a curved mirror to view teeth on the upper side of the mouth. Suppose she wants an upright image with a magnification of 2.20 when the mirror is 1.10 cm from a tooth. (Treat this problem as though the object and image lie along a straight line.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Graphical construction of an image from a mirror. What kind of mirror is needed? Use a ray diagram to decide, without performing any calculations. concave O convex Submit Previous Answers ✓ Correct y Set Up: += ₁ and m = == .m +2.20 and s= 1.10cm. An upright image must be virtual. y Solve: s' = Part B 음 and m- |f|= -f so m = + 허 . For a concave mirror, can be larger than 1.00. For a convex mirror, Ifl s+|f and m is always less than 1.00. The mirror must be concave (f > 0). What must be the focal length and radius of curvature of this mirror? Enter your answer in centimeters separated by a comma. 17| ΑΣΦ f. R= 2.42,4.84 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining ? cm

A dentist uses a curved mirror to view teeth on the upper side of the mouth. Suppose she wants an upright image with a magnification of 2.20 when the mirror is 1.10 cm from a tooth. (Treat this problem as though the object and image lie along a straight line.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Graphical construction of an image from a mirror. What kind of mirror is needed? Use a ray diagram to decide, without performing any calculations. concave O convex Submit Previous Answers ✓ Correct y Set Up: += ₁ and m = == .m +2.20 and s= 1.10cm. An upright image must be virtual. y Solve: s' = Part B 음 and m- |f|= -f so m = + 허 . For a concave mirror, can be larger than 1.00. For a convex mirror, Ifl s+|f and m is always less than 1.00. The mirror must be concave (f > 0). What must be the focal length and radius of curvature of this mirror? Enter your answer in centimeters separated by a comma. 17| ΑΣΦ f. R= 2.42,4.84 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining ? cm

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Applications Of Reflection Of Light

When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.

Sign Convention for Mirrors

A mirror is made of glass that is coated with a metal amalgam on one side due to which the light ray incident on the surface undergoes reflection and not refraction.

Question

A dentist uses a curved mirror to view teeth on the upper side of
the mouth. Suppose she wants an upright image with a
magnification of 2.20 when the mirror is 1.10 cm from a tooth.
(Treat this problem as though the object and image lie along a
straight line.)
For related problem-solving tips and strategies, you may want to
view a Video Tutor Solution of
Graphical construction of an image from a mirror.
What kind of mirror is needed? Use a ray diagram to decide, without performing any calculations.
concave
convex
Submit
Previous Answers
Correct
1
1
1
Set Up: +/=/ and m =
S
Solve: s'
Part B
=
sf
s-f
and m = -
|f|= -f so m = +·
Y
17 ΑΣΦ
f, R=2.42,4.84
=-.m = +2.20 and s = 1.10cm. An upright image must be virtual.
For a concave mirror, m can be larger than 1.00. For a convex mirror,
s-f
|f|
s+|f|
and m is always less than 1.00. The mirror must be concave (f> 0).
What must be the focal length and radius of curvature of this mirror?
Enter your answer in centimeters separated by a comma.
Submit Previous Answers Request Answer
X Incorrect; Try Again; 4 attempts remaining
?
cm

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