A DC series circuit includes a 9.0V battery and a 45.0 milli-Ohm resistor along with a switch. a.)Using either the computer drawing tools or a scanned hand written diagram, draw this circuit including proper symbols and labels. (Do not copy and paste an image from any other resource) b.) Find the current flowing through the resistor. (Show your work and label the direction the current is flowing in your diagram) c.) If power is heat dissipated, find the amount of heat dissipated by this resistor. Show your work.

A DC series circuit includes a 9.0V battery and a 45.0 milli-Ohm resistor along with a switch. a.)Using either the computer drawing tools or a scanned hand written diagram, draw this circuit including proper symbols and labels. (Do not copy and paste an image from any other resource) b.) Find the current flowing through the resistor. (Show your work and label the direction the current is flowing in your diagram) c.) If power is heat dissipated, find the amount of heat dissipated by this resistor. Show your work.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

## DC Series Circuit Analysis

### Problem Statement
A DC series circuit includes a 9.0V battery and a 45.0 milli-Ohm resistor along with a switch.

### Questions
#### a) Circuit Diagram
Using either computer drawing tools or a scanned handwritten diagram, draw this circuit including proper symbols and labels. (Do not copy and paste an image from any other resource.)

*Explanation*: Create a simple series circuit diagram consisting of:
- A 9.0V battery, typically represented by one long and one short parallel line.
- A resistor labeled as \( R = 45.0 \, \text{m}\Omega \).
- A switch that can either be open or closed, represented by a break in a line (open) or connected lines (closed).

#### b) Finding the Current
Find the current flowing through the resistor. (Show your work and label the direction the current is flowing in your diagram.)

*To calculate the current (\( I \)), use Ohm's Law:*
\[ I = \frac{V}{R} \]
where:
- \( V = 9.0 \, \text{V} \) (Voltage of the battery)
- \( R = 45.0 \, \text{m}\Omega = 45.0 \times 10^{-3} \, \Omega \)

*Steps:*
1. Convert the resistor value to Ohms:
\[ R = 45.0 \times 10^{-3} \, \Omega = 0.045 \, \Omega \]
2. Calculate the current:
\[ I = \frac{9.0 \, \text{V}}{0.045 \, \Omega} = 200 \, \text{A} \]

*The current flowing through the resistor is \( 200 \, \text{A} \). The direction of the current will be from the positive terminal of the battery, through the resistor, and back to the negative terminal of the battery.*

#### c) Heat Dissipated by the Resistor
If power is heat dissipated, find the amount of heat dissipated by this resistor. Show your work.

*To calculate the power (\( P \)) dissipated, use the formula:*
\[ P = I^2 R \]
where:
- \( I = 200 \, \text{A} \) (Current through the resistor)
-

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