2) Consider the circuit shown. a) Find the current in the 10 2 resistor with the switch open. b) Find the potential difference between points A and B. c) Find the current in each resistor when the switch is closed. 12V 68. BV
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Hi! I didn't really understand the first answer I got for this... Hoping someone else can help? Thank you so much!
Solution:
a) Apply kirchhoffs voltage law, for the loop formed when the switch is open,
This is the current flowing from 10 ohms resistance. Therefore, 0.2 A current flows from this resistance. The negative sign indicates that the current is flowing in the opposite direction to our assumption, that is the current flowing from the positive terminal of the 12-volt battery.
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