A data set includes data from student evaluations of courses. The summary statistics are n=88​, x=3.67​, s=0.52. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.75. Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Author:Carter
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Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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A data set includes data from student evaluations of courses. The summary statistics are

n=88​,
x=3.67​,
s=0.52.

Use a

0.05

significance level to test the claim that the population of student course evaluations has a mean equal to

3.75.

Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

# Hypothesis Testing of Student Evaluation Data

A data set includes data from student evaluations of courses. The summary statistics are as follows:
- Sample size (\(n\)) = 88
- Sample mean (\(\bar{x}\)) = 3.67
- Sample standard deviation (\(s\)) = 0.52

We use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.75. Assume that a simple random sample has been selected. 

The task is to identify the null and alternative hypotheses, determine the test statistic, calculate the P-value, and state the final conclusion that addresses the original claim.

## What are the null and alternative hypotheses?

Options:

- **A.** \( H_0: \mu = 3.75 \)  
  \( H_1: \mu > 3.75 \)

- **B.** \( H_0: \mu = 3.75 \)  
  \( H_1: \mu < 3.75 \)

- **C.** \( H_0: \mu = 3.75 \)  
  \( H_1: \mu \neq 3.75 \) ✔️

- **D.** \( H_0: \mu \neq 3.75 \)  
  \( H_1: \mu = 3.75 \)

The correct selection is option **C**, where the null hypothesis (\( H_0 \)) states that the mean is equal to 3.75, and the alternative hypothesis (\( H_1 \)) states that the mean is not equal to 3.75.

## Determine the Test Statistic

- Use the provided blue box to input the test statistic, and ensure to round to two decimal places as needed.
Transcribed Image Text:# Hypothesis Testing of Student Evaluation Data A data set includes data from student evaluations of courses. The summary statistics are as follows: - Sample size (\(n\)) = 88 - Sample mean (\(\bar{x}\)) = 3.67 - Sample standard deviation (\(s\)) = 0.52 We use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.75. Assume that a simple random sample has been selected. The task is to identify the null and alternative hypotheses, determine the test statistic, calculate the P-value, and state the final conclusion that addresses the original claim. ## What are the null and alternative hypotheses? Options: - **A.** \( H_0: \mu = 3.75 \) \( H_1: \mu > 3.75 \) - **B.** \( H_0: \mu = 3.75 \) \( H_1: \mu < 3.75 \) - **C.** \( H_0: \mu = 3.75 \) \( H_1: \mu \neq 3.75 \) ✔️ - **D.** \( H_0: \mu \neq 3.75 \) \( H_1: \mu = 3.75 \) The correct selection is option **C**, where the null hypothesis (\( H_0 \)) states that the mean is equal to 3.75, and the alternative hypothesis (\( H_1 \)) states that the mean is not equal to 3.75. ## Determine the Test Statistic - Use the provided blue box to input the test statistic, and ensure to round to two decimal places as needed.
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