A data set includes data from student evaluations of courses. The summary statistics are n=90, x= 3.93, s = 0.51.Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to4.00. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, teststatistic, P-value, and state the final conclusion that addresses the original claim.What are the null and alternative hypotheses?O A. Ho: μ#4.00H₁: μ = 4.00O C. Ho: μ = 4.00H₁:μ#4.00Determine the test statistic.(Round to two decimal places as needed.)Determine the P-value.(Round to three decimal places as needed.)State the final conclusion that addresses the original claim.Ho. There isevaluations is equal to 4.00B. Ho: μ = 4.00Hy: μ < 4.00correct.D. Ho: μ = 4.00H₁:μ>4.00evidence to conclude that the mean of the population of student courseNext

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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6) A researcher is interested in whether women like Justin Bieber's music more than men. The extent to which people liked Bieber's music was measured on a 10 point scale ranging from 1 = do not like at all, to 10 like Justin Bieber's music more than men (alpha = .05). very much like. Using the data below, please determine whether women Women Men 7 4 8 7 4 a) What type statistical analysis should you perform? Please explain your rationale b) Please state the null and alternative hypotheses c) Please write out the results (t-value, df, p-value) and make a decision d) Please make a general conclusion (no stats talk)
A newsletter publisher believes that 48 % of their readers own a laptop. A testing firm believes this is inaccurate and performs a test to dispute the publisher's claim. After performing a test at the 0.10 level of significance, the testing firm fails to reject the null hypothesis. What is the conclusion regarding the publisher’s claim?
A data set includes the counts of chocolate chips from three different types of Chips Ahoy cookies. The accompanying StatCrunch display shows results from analysis of variance used with those three types of cookies. Use a 0.05 significance level to test the claim that the three different types of cookies have the same mean number of chocolate chips. ANOVA table Source ns on Viewer Error Total DF SS MS F-Stat P-value 2 1235.5500 617.77500 62.2790 <0.0001 77 763.80000 9.9194805 79 1999.3500 Ho: H₁ H₂ H3 Determine the alternative hypothesis. H₁: At least one of the means is different from the others Determine the test statistic. The test statistic is 62.28. (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.)
A data set includes data from student evaluations of courses. The summary statistics are n=97, x=3.44, s=0.61. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternativehypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A. H0: μ=3.50 H1: μ≠3.50 B. H0: μ=3.50 H1: μ>3.50 C. H0: μ=3.50 H1: μ<3.50 D. H0: μ≠3.50 H1: μ=3.50 Determine the test statistic. nothing (Round to two decimal places as needed.) Determine the P-value. nothing (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. ▼ Fail to reject Reject H0. There is ▼ sufficient not sufficient evidence to conclude that the mean…
A random sample of 319 front-seat occupants involved in head-on collisions in a certain region resulted in 95 who sustained no injuries. We wish to use this sample data to test whether the true proportion of uninjured occupants in head-on collisions exceeds 0.25 or not. What would your conclusions be for this test of hypothesis, given a 5% significance level?
In a sample of 200 university professors, only 28 were woman. A newspaper claims that the proportion women professors in unis are less than 10%. Set up the hypothesis test for the newspapers claim and calculate the corresponding t-statistic rounded to 3.dp At 1% significance level th evidence does not refute the claim. True or false? Explain answer.
Use a y-test to test the claim o = 0.48 at the a = 0.01 significance level using sample statistics s = 0.466 and n = 15. Assume the population is normally distributed. Identify the null and alternative hypotheses. YA. Ho: o? = 0.48 O B. Ho: o 20.48 H:o +0.48 H,: o 0.48 Identify the test statistic. (Round to two decimal places as needed.)
A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?
Use the order statistics approach to estimate a 90% confidence interval of 95.1% VaR for a sample size of n = 1000 observations drawn from a normal distribution with zero mean and variance one.
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…
Assume that a simple random sample has been selected and test the given claim. Use the P-value method for testing hypotheses. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.The ages of actresses when they won an acting award is summarized by the statistics n=79, x=35.4 years, and s=11.4 years. Use a 0.05 significance level to test the claim that the mean age of actresses when they win an acting award is 32 years.Question content area bottomPart 1What are the hypotheses?A.H0: μ=32 yearsH1: μ≥32 yearsB.H0: μ≠32 yearsH1: μ=32 yearsC.H0: μ=32 yearsH1: μ<32 yearsD.H0: μ=32 yearsH1: μ≠32 yearsPart 2Identify the test statistic.t=enter your response here (Round to three decimal places as needed.)Part 3Identify the P-value.The P-value is enter your response here. (Round to four decimal places as needed.) Part 4State the final conclusion that addresses the original claim. Choose the…
A telephone poll of 500 adult Americans was reported in an issue of Time Magazine. One of the questions asked was “What is the main problem facing the country?” Thirty percent answered “crime”. We are interested in the population proportion of adult Americans who feel that crime is the main problem. Define the random variables X and P’ in words. Which distribution should be used for this problem? Explain your choice. Construct a 97% confidence interval for the population proportion of adult Americans who feel that crime is the main problem. i. State the confidence interval, ii. Sketch the graph, iii. Calculate the error bound 4. Suppose we want to lower the sampling error. What is one way to accomplish that?

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