A data set consisting of 175 standardized test scores is known to have a bell-shaped (normal) distributionwith a mean of 71 and a standard deviation of 9.Use the Empirical Rule to address the following questions.Hint: sketch the distribution to help visualize the problem.Approximately 95% of the test scores lie between 53and 89What approximate percentage of the test scores lie between the scores 44 and 98?What approximate percentage of the test scores lie between the scores 62 and 80?68Question Help: VideoSubmit Question

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Answered: A data set consisting of 175…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use z scores to compare the given values. The tallest living man at one time had a height of 225 cm. The shortest living man at that time had a height of 104.3 cm. Heights of men at that time had a mean of 173.55 cm and a standard deviation of 5.15 cm. Which of these two men had the height that was more extreme? Since the z score for the tallest man is z= and the z score for the shortest man is z= the V man had the height that was more extreme. (Round to two decimal places.)
For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 39 beats per minute, the mean of the listed pulse rates isx= 78.0 beats per minute, and their standard deviation is s = 20.7 beats per minute. a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 39 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between - 2 and 2 to be neither significantly low nor significantly high, significant? the pulse rate of 39 beats per minute a. The difference is beats per minute. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z = (Round to two decimal places as needed.) d. The lowest pulse rate is
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
The scores of students on a standardized test form a normal distribution with a mean of 300 and a standard deviation of 40. Using the fact that the middle 50% of the data falls within .67 standard deviations from the mean, find the lower and upper quartile scores for this test.
In a set of 48 months of data for medical the mean is 15 days and standard deviation of 4.2 how many months fewer than 19.2 days per month reported medical leave ( one standard deviation above the mean?
Suppose that the heights of adult men in the United States are normally distributed with a mean of 69 inches and a standard deviation of 3 inches. What proportion of adult men in the United States is at least 6 feet tall? (Hint 6 feet=72 inches.) Round answer to at least 4 decimal places.
Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 250 feet and a standard deviation of 44 feet. Let X = distance in feet for a fly ball. Find the 80th percentile of the distribution of fly balls. (Round your answer to one decimal place.)
On an intelligence test, the mean number of raw items correct is 236 and the standard deviation is 39. What are the raw (actual) scores on the test for people with IQs of (a) 119, (b) 81, and (c)100? To do this problem, first figure the Z score for the particular IQ score; then use that Z score to find the raw score. Note that IQ scores have a mean of 100 and a standard deviation of 15. (a) What is the raw (actual) score on the test for people with an IQ of 119?
Apply the Empirical Rule to solve the following: The weight of a newborn manatee calf is normally distributed with a mean of 66 lbs and a standard deviation of 4 lbs. (Do NOT overuse the calculator on this problem. Apply the Empirical Rule.) a.Draw and label the normal curve. (Don’t forget the word label on the x-axis) b.What percent of manatee calves have a birth weight between 54 and 78 lbs? c. What percent of manatee calves have a birth weight of more than 74 lbs? d .What is the birth weight of the middle 68% of manatee calves? e. What percent of manatee calves weigh more than 58 lbs at birth? f. How much do the smallest 0.15% of manatee calves weigh at birth? g. What percent of manatee calves weigh less than 62 lbs at birth? h. What percent of manatee calves weigh 66 lbs or more at birth?
The Alpha company takes a survey of the age for all employees. The average age is 35 with a standard deviation of 3.2 years. The results for a normal distribution curve. If the company has 985 workers, how many are over 44 years old?
Please answer the following: You can Thank you. Adult IQ scores can be modeled using a normal model with mean 100 and a standadrd deviation of 15. a. Find the prportion of IQ scores that are less than 115. b. Find the proportion of IQ scores that are greater than 131.5. c. Find the proportion of IQ scores between 90 and 110. d. Find the proportion of IQ scores that are betewwn 110 and 120. e. Find the IQ score above which there are 10% of the scores. f. Find the IQ score below which there are 20% of the scores.
The Graduate Record Examinations are widely used to help predict the performance of applicants to graduate schools. The range of possible scores on a GRE is 200 to 900. The psychology department finds that the scores of its applicants on the quantitative GRE are approximately normal with mean 544 and standard deviation 103. What score would a student need in order to score in the 90th percentile (90% or less) of those taking the test?

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