-A data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n = 196,x=7.83, s=2.23. Use a 0.05 significance level to test the claim that the population mean of such ratings is less than 8.00. Assume that asimple random sample has been selected Identify the null and alternative hypotheses, test statistic, P-value, and state the finalconclusion that addresses the original claimWhat are the null and alternative hypotheses?OA H₂ μ<8.00H₁μ> 8.00C. H₂ = 8.00H₁ μ<8.00Determine the test statistic.-1.07 (Round to two decimal places as needed)Determine the P-value0.005 (Round to three decimal places as needed)OB. Ho -8.00H₁ μ8.00OD. H₂ μ=8.00H₁ μ>8.00

As per the question, we were given a data set on speed dating that includes "like" ratings of male…

Answered: A data set about speed dating includes…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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An experiment was conducted on rodents to determine if the drug Haldol influenced the amount of "rough play." Five groups were included in the experiment. Subsequent behavior in terms of mean "rough play" behaviors was recorded. The output and box plot below, display the mean differences from baseline (i.e., after the drug was administered compared to before drug administration). What are the null and alternative hypotheses of this test? Summary of Roughplay differences Scd. Dev. Haldol dese Mean Freq. -.63158419 13.290618 19 Vehicle | 0.025 mg i 0.05 mg/ 1 0.1 mg/k -12.754389 13.783537 0.2 mg/k I 18 1.1481501 20.447041 5.0499951 16.035879 20 19 -20.S5 16.431064 20 Total -5.6631968 1B.558994 96 Analysis of Variance Frob F (p-value) Source SS df KS F Test- Statistic 8999.32832 4 2249.33203 9.63 0.0000 Between groups Within groups 91 260.682623 23722.1178 Tozal 32721.4461 95 344.436275 chif (4) 4.1710 Prob>chiz = 0.303 = Bartlett's test for equal variances: Roeghpiay diferences -50 Ho: 0…
A data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n= 191, x = 5.89, s = 1.96. Use a 0.10 significance level to test the claim that the population mean of such ratings is less than 6.00. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P- value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=6.00 O B. Ho: H=6.00 H;:µ#6.00 H: µ>6.00 O C. Ho: H6.00 H1:µ<6.00 Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence to conclude that the mean of the population of ratings is 6.00.
A data set includes data from 400 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.9 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. LOADING... Click the icon to view the display from technology. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=2.9 miles H1: μ<2.9 miles B. H0: μ=2.9 miles H1: μ>2.9 miles C. H0: μ<2.9 miles H1: μ=2.9 miles D. H0: μ=2.9 miles H1: μ≠2.9 miles
A data set includes data from student evaluations of courses. The summary statistics are n = 96, x 3.44, s 0.66. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H= 3.50 H1:H> 3.50 O B. Ho: u= 3.50 OC. Ho:H#3.50 H1:µ= 3.50 O D. Ho: H= 3.50 H1: µ#3.50 Determinhe test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence to conclude that the original claim that the mean of the population of student course evaluations is equal to 3.50 correct. Click to select your answer(s). F12 F10 吕0 F3 F6 FB F9 F7 F4 F5 esc F1 F2 & %23 24…
A data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n= 191, x= 6.83, s= 1.93. Use a 0.05 significance level to test the claim that the population mean of such ratings is less than 7.00. Assume that a simple random sample has been selected. Identify the null and altemative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and altenative hypotheses? OB. Ho: H7.00 H: µ>7.00 C. Họ: =7.00 OD. Ho: =7.00 Hp<7.00 H4: H#7.00 Determine the test statistic. (Round to two decimal places as needed.)
A data set includes data from student evaluations of courses. The summary statistics are nequals=8585, x overbarxequals=3.423.42, sequals=0.540.54. Use a 0.010.01 significance level to test the claim that the population of student course evaluations has a mean equal to 3.503.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Data were collected from 400 patients in the US about their estrogen level. Out of the 400, 35 patient have abnormal estrogen levels. On a national level, 8 % of patients have abnormal estrogen level. Researchers want to know the sample proportion differs from the national level. 5% is used for significance. Give the Ho and Ha. The appropriate test. Decision rule. Test calculations. Conclusion with comparison to alpha or critical value. I think this is a two tailed test. Use a one sample t- test. I think the null is rejected. t (40-1) = (400-35) / (.05 divided by sqrt 31) This is where I get stuck.
A z-test is to be performed for a population mean. Express the decision criterion for the hypothesis test in terms of x. That is, determine for what values of x the null hypothesis would be rejected. ala After training intensively for six months, John hopes that his mean time to run 100 meters has decreased from last year's mean time of 11.8 seconds. He performs a hypothesis test to determine whether his mean time has decreased. Preliminary data analyses indicate that it is reasonable to apply a z-test. The hypotheses are Ho:u= 11.8 seconds H:u11.64 O Reject H, if x 11.61 Submit Assignment 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy II
identify the test statistic. Identify the P-value.
The mean potassium content of a popular sports drink is listed as 132 mg in a 32-oz bottle. Analysis of 24 bottles indicates a sample mean of 131.2 mg. (a) State the hypotheses for a two-tailed test of the claimed potassium content.. a. Ho: μ= 132 mg vs. H₁: b. He: ≤132 mg vs. H₁: c. He: ≥132 mg vs. H₁: Oa Ob Oc (b) Assuming a known standard deviation of 2.1 mg, calculate the z test statistic to test the manufacturer's claim. (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.) Test statistic 132 mg >132 mg <132 mg (c) At the 2 percent level of significance (a = .02) does the sample contradict the manufacturer's claim? Decision Rule: Reject Ho
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