+ A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. :Z: H A) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a high electron density. The electrons follow the arrow from the oxygen of the oxonium to the hydrogen. In a second arrow, this electron rich hydrogen atom bonds to the nitrogen of the diisopropylamine showing the formation of a new bond. B) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a high electron density. The electrons follow the arrow from the basic amine to this hydrogen showing the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the oxonium breaking the O-H bond. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a low electron density. The electrons follow the arrow from this proton to the nitrogen of the diisopropylamine resulting in the formation of a new bond. The second arrow indicates the electrons from the O-H bond D 3:35 PM
+ A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. :Z: H A) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a high electron density. The electrons follow the arrow from the oxygen of the oxonium to the hydrogen. In a second arrow, this electron rich hydrogen atom bonds to the nitrogen of the diisopropylamine showing the formation of a new bond. B) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a high electron density. The electrons follow the arrow from the basic amine to this hydrogen showing the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the oxonium breaking the O-H bond. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a low electron density. The electrons follow the arrow from this proton to the nitrogen of the diisopropylamine resulting in the formation of a new bond. The second arrow indicates the electrons from the O-H bond D 3:35 PM
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 7P
Related questions
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![+
Question 10 of 21
A curved arrow mechanism for a Bronsted acid-base reaction is shown below.
Choose the best explanation for this proposed curved arrow mechanism.
H
A) The arrow points at the proton that is
electron rich. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a high electron density. The
electrons follow the arrow from the oxygen of
the oxonium to the hydrogen. In a second
arrow, this electron rich hydrogen atom bonds.
to the nitrogen of the diisopropylamine showing
the formation of a new bond.
B) The arrow points at the proton that is
electron rich. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a high electron density. The
electrons follow the arrow from the basic amine
to this hydrogen showing the formation of a
new bond. The second arrow indicates the
electrons from the O-H bond moving to the
oxygen of the oxonium breaking the O-H bond.
C) The arrow points at the proton that is
electron deficient. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a low electron density. The
electrons follow the arrow from this proton to
the nitrogen of the diisopropylamine resulting in
the formation of a new bond. The second arrow
indicates the electrons from the O-H bond.
Submit
D 3:35 PM](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F942b9f9d-69bc-408e-a317-90fc1c8c699d%2F9aa3d234-8001-463c-86c0-4c3892d0546d%2Fj3f9ome_processed.jpeg&w=3840&q=75)
Transcribed Image Text:+
Question 10 of 21
A curved arrow mechanism for a Bronsted acid-base reaction is shown below.
Choose the best explanation for this proposed curved arrow mechanism.
H
A) The arrow points at the proton that is
electron rich. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a high electron density. The
electrons follow the arrow from the oxygen of
the oxonium to the hydrogen. In a second
arrow, this electron rich hydrogen atom bonds.
to the nitrogen of the diisopropylamine showing
the formation of a new bond.
B) The arrow points at the proton that is
electron rich. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a high electron density. The
electrons follow the arrow from the basic amine
to this hydrogen showing the formation of a
new bond. The second arrow indicates the
electrons from the O-H bond moving to the
oxygen of the oxonium breaking the O-H bond.
C) The arrow points at the proton that is
electron deficient. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a low electron density. The
electrons follow the arrow from this proton to
the nitrogen of the diisopropylamine resulting in
the formation of a new bond. The second arrow
indicates the electrons from the O-H bond.
Submit
D 3:35 PM
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