A curious CHEM 32.1 student wanted to determine the levels of Fe (FM = 55.85), Al (FM = 26.982) and Pb (FM = 207.2) in a wastewater effluent from a powerplant near their place. To do so, he obtained 100 mL of the water sample for analysis. After appropriate sample preparation, he added 10.00 mL of 0.100 M sodium tartrate to prevent the precipitation of Pb. Then, he added NH3 dropwise, which results to precipitation of hydrated Al(OH)3 and Fe(OH)3. After filtration and washing, the student ignited the residue, giving 0.6127 g dry Al2O3 (FM = 101.96) and Fe2O3 (FM=159.69). When heated under a stream of H2, Al2O3 is unchanged, but Fe2O3 was converted to Fe(s) and H2O(g) , giving a residue that weighs 0.4967 g. Meanwhile, he added excess amount of concentrated H2SO4 in the filtrate, which results to precipitation of PbSO4 (FM = 303.26) weighing 0.1317 g after drying. Given these information, calculate the ppm Fe, ppm Al, and ppm Pb in the effluent
A curious CHEM 32.1 student wanted to determine the levels of Fe (FM = 55.85), Al (FM = 26.982) and Pb (FM = 207.2) in a wastewater effluent from a powerplant near their place. To do so, he obtained 100 mL of the water sample for analysis. After appropriate sample preparation, he added
10.00 mL of 0.100 M sodium tartrate to prevent the precipitation of Pb. Then, he added NH3 dropwise, which results to precipitation of hydrated Al(OH)3 and Fe(OH)3. After filtration and washing, the student ignited the residue, giving 0.6127 g dry Al2O3 (FM = 101.96) and Fe2O3 (FM=159.69). When heated under a stream of H2, Al2O3 is unchanged, but Fe2O3 was converted to Fe(s) and H2O(g) , giving a residue that weighs 0.4967 g. Meanwhile, he added excess amount of concentrated H2SO4 in the filtrate, which results to precipitation of PbSO4 (FM = 303.26) weighing
0.1317 g after drying. Given these information, calculate the ppm Fe, ppm Al, and ppm Pb in the effluent.
Trending now
This is a popular solution!
Step by step
Solved in 7 steps
