A cup of rather dilute hot tea initially at 140 degrees F is served to a customer at Howard Johnson's. Unfortunately, before they get around to drinking it, it has spontaneously cooled off to 100 degrees F. Suppose that our customer complains about the cold tea and is given a second cup of hot tea. Feeling especially hungry (for tea?) they mix the hot tea and the cold tea together so that they will have twice as much tea (albeit luke warm). Assuming that the mixing occurs spontaneously and adiabatically, what is the final temperature of the tea, the change in entropy of the tea, and the change in entropy of the universe for the mixing process? The temperature of the restaurant (the surroundings) is 70 degrees F. The tea has a mass of 200g.

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A cup of rather dilute hot tea initially at 140 degrees F is served to a customer at Howard Johnson's.
Unfortunately, before they get around to drinking it, it has spontaneously cooled off to 100 degrees F.
Suppose that our customer complains about the cold tea and is given a second cup of hot tea. Feeling
especially hungry (for tea?) they mix the hot tea and the cold tea together so that they will have twice as
much tea (albeit lyke warm). Assuming that the mixing occurs spontaneously and adiabatically, what is
the final temperature of the tea, the change in entropy of the tea, and the change in entropy of the
universe for the mixing process? The temperature of the restaurant (the surroundings) is 70 degrees F.
The tea has a mass of 200g.
Transcribed Image Text:A cup of rather dilute hot tea initially at 140 degrees F is served to a customer at Howard Johnson's. Unfortunately, before they get around to drinking it, it has spontaneously cooled off to 100 degrees F. Suppose that our customer complains about the cold tea and is given a second cup of hot tea. Feeling especially hungry (for tea?) they mix the hot tea and the cold tea together so that they will have twice as much tea (albeit lyke warm). Assuming that the mixing occurs spontaneously and adiabatically, what is the final temperature of the tea, the change in entropy of the tea, and the change in entropy of the universe for the mixing process? The temperature of the restaurant (the surroundings) is 70 degrees F. The tea has a mass of 200g.
Expert Solution
Step 1

As the mixing process is adiabatic, no heat is lost to the surroundings.

So, Q = H = 0, where H is the change in enthalpy.

Enthalpy H = m×H^, where

m is the mass

H^ is the specific enthalpy.

Here, as the values for tea is not given, we consider the values for water instead.

 

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