A cube is dropped into the cylinder and the water rises. The length of a side of the cube is 3.7 cm. Specific weight of water is 9.81 kN/m3. Find the density of the cube, the specific gravity of the cube. Where is the vertical CG of the cube? Vertical center of buoyancy based on SWL?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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A cube is dropped into the cylinder and the water rises. The length of a side of the cube is 3.7 cm. Specific weight of water is 9.81 kN/m3.

Find the density of the cube, the specific gravity of the cube. Where is the vertical CG of the cube? Vertical center of buoyancy based on SWL?

### Measuring the Volume of an Object Using a Graduated Cylinder

#### Diagram Explanation

The image shows two graduated cylinders with a capacity of 250 mL each, marked with a precision of 5 mL at 20°C.

- **Left Cylinder**: 
  - Contains a liquid up to the 150 mL mark. This represents the initial volume of the liquid before any object is submerged.

- **Right Cylinder**: 
  - Contains the same liquid, but an object has been submerged, raising the liquid level to the 200 mL mark. This increase indicates the volume of the submerged object.

#### Volume Calculation

To find the volume of the object:
  
1. **Initial Volume of Liquid**: 150 mL
2. **Final Volume with Object**: 200 mL
3. **Volume of Object** = Final Volume - Initial Volume = 200 mL - 150 mL = 50 mL

This method is a practical application of Archimedes’ principle and is often used in laboratory settings to measure the volume of irregularly shaped objects.
Transcribed Image Text:### Measuring the Volume of an Object Using a Graduated Cylinder #### Diagram Explanation The image shows two graduated cylinders with a capacity of 250 mL each, marked with a precision of 5 mL at 20°C. - **Left Cylinder**: - Contains a liquid up to the 150 mL mark. This represents the initial volume of the liquid before any object is submerged. - **Right Cylinder**: - Contains the same liquid, but an object has been submerged, raising the liquid level to the 200 mL mark. This increase indicates the volume of the submerged object. #### Volume Calculation To find the volume of the object: 1. **Initial Volume of Liquid**: 150 mL 2. **Final Volume with Object**: 200 mL 3. **Volume of Object** = Final Volume - Initial Volume = 200 mL - 150 mL = 50 mL This method is a practical application of Archimedes’ principle and is often used in laboratory settings to measure the volume of irregularly shaped objects.
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