A crate of fruit with a mass of 40.0 kg and a specific heatcapacity of 3550 J/(kg. K) slides 9.00 m down a rampinclined at an angle of 40.0 degrees below the horizontal.Part AIf the crate was at rest at the top of the incline and has a speed of 2.55 m/s at the bottom, how much work Wf was done on the crate by friction?Use 9.81 m/s² for the acceleration due to gravity and express your answer in joules.► View Available Hint(s)Wf= -2140 JSubmitCorrectThe frictional force opposes the motion of the crate, so the work done on the crate by friction must be a negative quantity.Part BPrevious AnswersIf an amount of heat equal to the magnitude of the work done by friction is absorbed by the crate of fruit and the fruit reaches a uniform finaltemperature, what is its temperature change AT?► View Available Hint(s)AT =ΑΣΦW

Answered: Image /qna-images/answer/d04bf0f6-4540-4d2e-871c-ea02208e7ff0.jpg

A crate of fruit with mass of 40.0 kg and a specific heat capacity of 3550 J/(kg. K) slides 9.00 m down a ramp inclined at an angle of 40.0 degrees below the horizontal. Part A If the crate was at rest at the top of the incline and has a speed of 2.55 m/s at the bottom, how much work W, was done on the crate by friction? Use 9.81 m/s² for the acceleration due to gravity and express your answer joules. View Available Hint(s) W₁ = -2140 J Submit Correct The frictional force opposes the motion the crate, so the work done on the crate by friction must be a negative quantity. Part B Previous Answers If an amount of heat equal to the magnitude of the work done by friction is absorbed by the crate of fruit and the fruit reaches a uniform final temperature, what is its temperature change AT? ▸ View Available Hint(s) ΔΤ' = IVE ΙΑΣΦ 1 ? °C

A crate of fruit with mass of 40.0 kg and a specific heat capacity of 3550 J/(kg. K) slides 9.00 m down a ramp inclined at an angle of 40.0 degrees below the horizontal. Part A If the crate was at rest at the top of the incline and has a speed of 2.55 m/s at the bottom, how much work W, was done on the crate by friction? Use 9.81 m/s² for the acceleration due to gravity and express your answer joules. View Available Hint(s) W₁ = -2140 J Submit Correct The frictional force opposes the motion the crate, so the work done on the crate by friction must be a negative quantity. Part B Previous Answers If an amount of heat equal to the magnitude of the work done by friction is absorbed by the crate of fruit and the fruit reaches a uniform final temperature, what is its temperature change AT? ▸ View Available Hint(s) ΔΤ' = IVE ΙΑΣΦ 1 ? °C

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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