**Constants and Other Possibly Useful Numbers**- **Gravitational acceleration (g)**: \(9.8 \, \text{m/s}^2\)- **Gravitational constant (G)**: \(6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2\)- **Speed of light (c)**: \(3 \times 10^8 \, \text{m/s}\)- **Mass of an electron (\(m_e\))**: \(9.11 \times 10^{-31} \, \text{kg}\)- **Mass of a proton (\(m_p\))**: \(1.67 \times 10^{-27} \, \text{kg}\)- **Mass of Earth**: \(6 \times 10^{24} \, \text{kg}\)- **Radius of Earth**: \(6.4 \times 10^6 \, \text{m}\)- **Mass of the Moon**: \(7.35 \times 10^{22} \, \text{kg}\)- **Radius of the Moon**: \(1.74 \times 10^6 \, \text{m}\)- **Mass of the Sun**: \(2 \times 10^{30} \, \text{kg}\)- **Radius of the Sun**: \(6.957 \times 10^8 \, \text{m}\)- **Average distance between the Moon and Earth**: \(3.84 \times 10^8 \, \text{m}\)- **Average distance between the Sun and Earth**: \(1.5 \times 10^{11} \, \text{m}\)**Moments of Inertia:**- \(I = \sum m_i r_i^2\)- \(I_{\text{ring}} = M \left( \frac{R_1^2 + R_2^2}{2} \right)\)- \(I_{\text{disk}} = I_{\text{cylinder}} = \frac{1}{2} M R^2\)- \(I_{\text{rod}} = \frac{1}{12} M L^2\)- \(I_{\text{sphere}} = \frac{2}{5 Title: Understanding Work and Friction in PhysicsA parent pulls a child in a wagon at a constant speed, exerting a force of \( F = 55N \) at an angle of \( 30^\circ \) with respect to the horizontal sidewalk.**Problems:**(a) How much work do they do if they pull the wagon for a distance of 30m?(b) What is the force of friction on the wagon?---**Explanation:**- **Force and Angle:** The parent is using a force of 55 Newtons at a 30-degree angle to the horizontal. - **Work Calculation:** To find the work done, consider the horizontal component of the force. - **Friction:** Since the wagon moves at a constant speed, the force of friction counteracts the horizontal force component. Use this to find the force of friction.By applying these principles, one can solve for the work done and the force of friction, enhancing understanding of basic physics concepts such as force vectors and work.

Given Data Applied force on the wagon is F=55 N Angle of the force with respect to the horizontal is…

A parent pulls a child in a wagon at a constant speed, exerting a force of F = 55N at an angle of 30° with respect to the horizontal sidewalk. (a) How much work do they do, if they pull the wagon for a distance of 30m? (b) What is the force of friction on the wagon?

A parent pulls a child in a wagon at a constant speed, exerting a force of F = 55N at an angle of 30° with respect to the horizontal sidewalk. (a) How much work do they do, if they pull the wagon for a distance of 30m? (b) What is the force of friction on the wagon?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Constants and Other Possibly Useful Numbers**

- **Gravitational acceleration (g)**: \(9.8 \, \text{m/s}^2\)
- **Gravitational constant (G)**: \(6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2\)
- **Speed of light (c)**: \(3 \times 10^8 \, \text{m/s}\)

- **Mass of an electron (\(m_e\))**: \(9.11 \times 10^{-31} \, \text{kg}\)
- **Mass of a proton (\(m_p\))**: \(1.67 \times 10^{-27} \, \text{kg}\)

- **Mass of Earth**: \(6 \times 10^{24} \, \text{kg}\)
- **Radius of Earth**: \(6.4 \times 10^6 \, \text{m}\)

- **Mass of the Moon**: \(7.35 \times 10^{22} \, \text{kg}\)
- **Radius of the Moon**: \(1.74 \times 10^6 \, \text{m}\)

- **Mass of the Sun**: \(2 \times 10^{30} \, \text{kg}\)
- **Radius of the Sun**: \(6.957 \times 10^8 \, \text{m}\)

- **Average distance between the Moon and Earth**: \(3.84 \times 10^8 \, \text{m}\)
- **Average distance between the Sun and Earth**: \(1.5 \times 10^{11} \, \text{m}\)

**Moments of Inertia:**

- \(I = \sum m_i r_i^2\)
- \(I_{\text{ring}} = M \left( \frac{R_1^2 + R_2^2}{2} \right)\)
- \(I_{\text{disk}} = I_{\text{cylinder}} = \frac{1}{2} M R^2\)
- \(I_{\text{rod}} = \frac{1}{12} M L^2\)
- \(I_{\text{sphere}} = \frac{2}{5

Title: Understanding Work and Friction in Physics

A parent pulls a child in a wagon at a constant speed, exerting a force of \( F = 55N \) at an angle of \( 30^\circ \) with respect to the horizontal sidewalk.

**Problems:**

(a) How much work do they do if they pull the wagon for a distance of 30m?

(b) What is the force of friction on the wagon?

---

**Explanation:**

- **Force and Angle:** The parent is using a force of 55 Newtons at a 30-degree angle to the horizontal.

- **Work Calculation:** To find the work done, consider the horizontal component of the force.

- **Friction:** Since the wagon moves at a constant speed, the force of friction counteracts the horizontal force component. Use this to find the force of friction.

By applying these principles, one can solve for the work done and the force of friction, enhancing understanding of basic physics concepts such as force vectors and work.

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