A converging thin lens has a focal length of 50 cm in air. When immersed in a liquid, its focal length is measured to be 250 cm. If the index of refraction of the lens is 1.5, then determine the index of the liquid.
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Q: A converging lens has a focal length of 15.5 cm. An object with a height of 6.1 cm is placed 36.4 cm…
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A: u = -21 cm v = -(25-2) = -23 cm Since near point is 25 cm from eye
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Q: A lighted candle is placed 39.0 cm in front of a diverging lens. The light passes through the…
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- The owner of a van installs a rear-window lens that has a focal length of -0.300 m. When the owner looks out through the lens at an object located directly behind the van, the object appears to be 0.240 m from the back of the van, and appears to be 0.350 m tall. (a) How far from the van is the object actually located, and (b) how tall is the object?If the screen is at the right position and the object is in a right position, the lens will focus the image of the object onto the screen. If the screen is anywhere else, the object will look blurry or won't be seen. The optical table has a meter-tape attached to the side, to give the position of the items. If the object is in a wrong position, the lens will defocus the light -- spread it out. That means that the screen can't be placed anywhere to display a focused image. If xL = 32.7 cm and the focal length is f = 20.8 cm, give a position (xO) that results in the light from the object spreading out. (There are infinitely many such positions.)When a patient is being fitted with contact lenses, the curvature of the patient's cornea is measured with an instrument known as a keratometer. A lighted object is held near the eye, and keratometer measures the magnification of the image formed by the reflection from the front of the cornea. If an object is held 10.0cm in front of a patient's eye, and the reflected image is magnified by a factor of 0.035, what is the radius of curvature of the patient's cornea?
- Compute the focal length of a diverging thin lens made of flint glass, whose refractive index is 1.66 and is immersed in air having refractive index 1. The radii of the spherical surfaces of the lens are 10 cm and 20 cm. Select one: O -30 cm O O -10 cm 30 cm 10 cmWhat is the focal length of the lens in your eye when you can focus on an object at your near point? Assume that the distance from your lens to the back of your eye is 2.0 cm, that your near point is 21 cm in front of your lens, and that the liquid behind the lens has n=1.00 just like the air in front of your lens. (a) 1.8 cm (b) 18 cm (c) 2.1 cm (d) 21 cm (e) None of the above.It is your first day at work as a summer intern at an optics company. Your supervisor hands you a diverging lens and asks you to measure its focal length. You know that with a converging lens, you can measure the focal length by placing an object a distance ss to the left of the lens, far enough from the lens for the image to be real, and viewing the image on a screen that is to the right of the lens. By adjusting the position of the screen until the image is in sharp focus, you can determine the image distance s′s′ and then use the equation 1s+1s′=1f1s+1s′=1f, to calculate the focal length ff of the lens. But this procedure won't work with a diverging lens−−by itself, a diverging lens produces only virtual images, which can't be projected onto a screen. Therefore, to determine the focal length of a diverging lens, you do the following: First you take a converging lens and measure that, for an object 20.0 cmcm to the left of the lens, the image is 29.7 cmcm to the right of the lens.…
- An object is placed in front of a diverging lens whose focal length is - 30.7 cm. A virtual image is formed whose height is 0.532 times the object height. How far is the object from the lens?A man standing 1.54 m in front of a shaving mirror produces an inverted image 18.6 cm in front of it. How close to the mirror should he stand if he wants to form an upright image of his chin that is twice the chin's actual size? cm A contact lens is made of plastic with an index of refraction of 1.40. The lens has an outer radius of curvature of +1.92 cm and an inner radius of curvature of +2.47 cm. What is the focal length of the lens? cmAn object is placed 21.2 cm in front of a diverging lens which has a focal length with a magnitude of 13.0 cm. How far in front of the lens should the object be placed in order to produce an image that is reduced by a factor of 3.15?