A converging lens forms an image of an 8.00-mm-tall real object. The image is 12.0 cm to the left of the lens, 3.40 cm tall, and erect. What is the focal length of the lens? Where is the object located?
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A converging lens forms an image of an 8.00-mm-tall real
object. The image is 12.0 cm to the left of the lens, 3.40 cm tall,
and erect. What is the focal length of the lens? Where is the object
located?
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- When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20 cm-tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated by a comma. s₁, y = 120,2.40 cm Submit Correct Set Up: Apply Solve: Lens 1: m₁ = Previous Answers Part B $1 f₁ $1-f₁ $₂,|y₂| = 1 S s' 1 S +1/1 = = gives (60.0 cm) (40.0 cm) 60.0 cm-40.0 cm to each lens. m₁ 120 cm 60.0 cm = = -2.00 = Y'₁ Y1 120 cm and m2 $1…A 2.0-cm-tall candle flame is 2.0 m from a wall. You happen to have a lens with a focal length of 32 cm. How many places can you put the lens to form a well-focused image of the candle flame on the wall? For each location, what are the height and orientation of the image?A converging lens with a focal length of 70.0 cm forms an image of a 3.20-cm-tall real object that is to the left of the lens. The image is 4.50 cm tall and inverted. Where are the object and image located in relation to the lens? Is the image real or virtual?
- You hold a magnifying glass 4.0 cm above 1.98 mm-long bug and the image is 5.44 mm long. What is the focal length of the lens? Please give your answer in cm.A lens forms an image of an object. The object is 16.0 cm from the lens. The image is 12.0 cm from the lens on the same side as the object. (a) What is the focal length of the lens? Is the lens converging or diverging? (b) If the object is 8.50 mm tall, how tall is the image? Is it erect or inverted? (c) Draw a principal-ray diagram.Two converging lenses have the same focal length of 5.00 cm. They have a common principal axis and are separated by 29.5 cm. An object is located 10.0 cm to the left of the left-hand lens. What is the image distance (relative to the lens on the right) of the final image produced by this two-lens system? Final image distance = Number i Units
- an object is placed 19.0 cm to the left of a lenss of the focal length 12.0cm. 27.0 cm to the right of this lens is a plane mirror. Where does the final image form? - 5.56 cm to the right of the mirror -5.56 cm to the left of the mirro - 21.4 cm to the left of the lens -32.6 cm to the left of the lens -19.6 cm to the left of the mirrorWhen two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.60-cm-tall object is 52.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cmcm, is located 300 cm to the right of the first lens along the same optic axis. Find the location and height of the image (call it I1) formed by the lens with a focal length of 40.0 cm. I1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.The widest cinema screen in the world was reportedly constructed in New Zealand in 2007. The screen is 30.6 meters (100 feet) wide. Images from a 35-mm wide film are projected onto this screen. Suppose that the screen in the theater is located a distance of 46 m from the projector. Determine the magnification of the image and the focal length of the lens system.
- When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20-cm-tall object is 50.0 cm to the left of a lens of focal length of magnitude 40.0 cm. A second lens, this one having a focal length of magnitude 60.0 cm, is located 300.0 cm to the right of the first lens along the same optic axis.One side of a lens is convex with radius of curvature 30 cm. The other side is concave with radius of curvature 50 cm. The index of refraction of the lens is 1.6. What is the focal length of the lens? Group of answer choices 130 cm, converging 130 cm, diverging 31 cm, converging 31 cm, divergingYou have a lens whose focal length is -5.05 cm. You place an object on the axis of the lens at a distance of 12.1 cm from it. How far is the object's image from the lens? Enter the answer as a positive quantity. image distance: cm If it can be determined, is the image real or virtual? real virtual cannot be determined If it can be determined, is the image upright or inverted with respect to the object? cannot be determined inverted upright