A container holding 4.20 kg of water at 20.0°C is placed in a freezer that is kept at -20O.0°C. The water freezes and comes to thermal equilibrium with the interior of the freezer. What is the minimum amount of electrical energy required by the freezer to do this if it operates between reservoirs at temperatures of 20.0°C and -20.0°C? (Latent heat of fusion of ice = 333,700 J/ kg, specific heat capacity of water = 4186 J/(kg-K), specific heat capacity of ice = 2100 J/(kg- K)). |kJ

A container holding 4.20 kg of water at 20.0°C is placed in a freezer that is kept at -20O.0°C. The water freezes and comes to thermal equilibrium with the interior of the freezer. What is the minimum amount of electrical energy required by the freezer to do this if it operates between reservoirs at temperatures of 20.0°C and -20.0°C? (Latent heat of fusion of ice = 333,700 J/ kg, specific heat capacity of water = 4186 J/(kg-K), specific heat capacity of ice = 2100 J/(kg- K)). |kJ

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter18: Heat Engines, Entropy, And The Second Law Of Thermodynamics

Section: Chapter Questions

Problem 45P

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Question

A container holding 4.20 kg of water at 20.0°C is placed in a freezer that is kept at -20.0°C. The water freezes and comes to thermal
equilibrium with the interior of the freezer. What is the minimum amount of electrical energy required by the freezer to do this if it
operates between reservoirs at temperatures of 20.0°C and –-20.0°C? (Latent heat of fusion of ice =
capacity of water = 4186 J/(kg K), specific heat capacity of ice = 2100 J/(kg K)).
333,700 J/ kg, specific heat
kJ

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