(a) Construct a stem-and-leaf display of the data. (Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.) Stems Leaves 1 . 32 33 CO 34 NONE 35 1349 36 h257 9 37 4589 38 39 3568 40 3 9 NONE 41 42 3 How does it suggest that the sample mean and median will compare? O The display is reasonably symmetric, so the mean and median will be close The display is negatively skewed, so the mean will be greater than the median The display is positively skewed, so the mean will be greater than the median The display is negatively skewed, so the median will be greater than the mean. The display is positively skewed, so the median will be greater than the mean. (b) Calculate the values of the sample mean x and median X. [Hint: £xj = 9642.] (Round your answers to two decimal places.) 370.85 х sec X 370 sec (c) By how much could the largest time, currently 423, be increased without affecting the value of the sample median? (Enter o if there is no limit to the amount.) By how much could this value be decreased without affecting the value of the sample median? (Enter o if there is no limit to the amount.) f X (d) What are the values of x and X when the observations are reexpressed in minutes? (Round your answers to two decimal places.) min = 6.17 х min 6.17

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) to complete the escape:

389	351	354	361	379	423	321	396	403
374	375	371	362	367	365	327	338	395
393	369	378	359	353	409	332	398

I have uploaded a picture with the full problem. I need help in the 2 questions I got wrong. On the picture the table is already set in order from smaller to bigger.

By how much could this value be decreased without affecting the value of the sample median? (Enter ∞ if there is no limit to the amount.) I have no idea on how to calculate that.

The other question is all the way down. I know I have to conver the seconds to minutes. I got 370.85 / 60 = 6.1695 which if I round to 2 decimal places as asked by the problem I should be getting 6.17 minutes. I was marked wrong. Why?

Thanks.

(a) Construct a stem-and-leaf display of the data. (Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
Stems
Leaves
1 .
32
33
CO
34
NONE
35
1349
36
h257 9
37
4589
38
39
3568
40
3 9
NONE
41
42
3
How does it suggest that the sample mean and median will compare?
O The display is reasonably symmetric, so the mean and median will be close
The display is negatively skewed, so the mean will be greater than the median
The display is positively skewed, so the mean will be greater than the median
The display is negatively skewed, so the median will be greater than the mean.
The display is positively skewed, so the median will be greater than the mean.
(b) Calculate the values of the sample mean x and median X. [Hint: £xj = 9642.] (Round your answers to two decimal places.)
370.85
х
sec
X
370
sec
(c) By how much could the largest time, currently 423, be increased without affecting the value of the sample median? (Enter o if there is no limit to the
amount.)
By how much could this value be decreased without affecting the value of the sample median? (Enter o if there is no limit to the amount.)
f
X
(d) What are the values of x and X when the observations are reexpressed in minutes? (Round your answers to two decimal places.)
min
= 6.17
х
min
6.17

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

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