A concave lens has an object located on its principal axis 32.6 cm from the its vertical axis. A virtual image is formed 38.3 cm from its vertical axis. What is the focal length of the lens?
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A: Given:- fmirror = 12 cm flens = 10 cm
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Q: A thin lens is comprised of two spherical surfaces with radii of curvatures of 34 cm for the front…
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A: For the objective lens, the lens equation is given by
Q: A transparent photographic slide is placed in front of a converging lens with a focal length of 2.33…
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Q: The figure shows an object and its image formed by a thin lens. Assume that d1 = 0.552 m, d2 = 0.398…
A: Object distance (u)= d1=0.552 m Image distance (v)=
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Q: 5. The optical system consists of two lenses, of focal lengths D cm converging lens on the left side…
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Q: One side of a lens is convex with radius of curvature 30 cm. The other side is concave with radius…
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Q: A glass lens (?=1.60) has a focal length of ?=−32.7 cm and a plano‑concave shape. Calculate the…
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Q: [ Lens-Maker Formula: A plano-convex lens is to have a focal length of magnitude 40 cm, and it is…
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- An object is placed in 5 cm in front of a lens, producing an image that is upright and 3 times larger, m = +3. Determine the position of the image and the focal length of the lens.An object is placed at a distance of 10.0 cm from a convex lens with a focal length of 15.0 cm, and a virtual image is formed . Calculate the magnification factor for the image.A transparent photographic slide is placed in front of a converging lens with a focal length of 2.20 cm. An image of the slide is formed 14.5 cm from the slide. (a) How far is the lens from the slide if the image is real? (b) How far is the lens from the slide if the image is virtual? Step 1 (a) The real image case is shown in the ray diagram. or Object 1 Figure 1 + P 14.5 cm P Notice that here p + q = 14.5 cm, or q = 14.5 cm - p. The thin-lens equation, with focal length f = 2.20 cm, gives 1 - p² (14.5 cm)p+ p+q = F Description Image | cm² = 0. Using the quadratic formula to solve the above equation gives two solutions. The smaller solution is p= cm and the larger solution is p = cm cm. Both are valid solutions for the real image case.
- A double-convex lens has a focal length of 6.00cm. (a) How far away from an insect 2.00mm long should the lens be held in order to produce an upright image 5.00mm long? (b) What is the image distance? A. p = +3.6 cm and q = -9 cm B. p = +3.6 cm and q = +9 cm C. p = -3.6 cm and q = -9 cm D. p = -3.6 cm and q = +9 cmAn object is placed 36cm to the left of a converging lens. The resulting image is five times the size of the object and projected onto a screen. What is the focal length of this lens?Contact lenses are placed right on the eyeball, so the distance from the eye to an object (or image) is the same as the distance from the lens to that object (or image). A certain person can see distant objects well, but his near point is 46.0cm from his eyes instead of the usual 25.0cm .If the correcting lenses will be contact lenses, what focal length lens is needed ?
- A contact lens is made of plastic with an index of refraction of 1.60. The lens has an outer radius of curvature of +1.96 cm and an inner radius of curvature of +2.48 cm. What is the focal length of the lens?The focal points of a diverging lens are 25.0 cm from the lens. An object is placed 15.0 cm in front of the lens. What is the magnification of the image produced?A convex lens has a focal length of 16 cm. A candle with a height of 6 cm is 15 cm away from the lens. Find the location of the image. If the image is real give a positive answer and a virtual image should be a negative answer.