An object is placed in 5 cm in front of a lens, producing an image that is upright and 3 times larger, m = +3. Determine the position of the image and %3D the focal length of the lens.
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- can someone help me with this physics problemSuppose a certain person's visual acuity is such that he can see objects clearly that form an image 4.00 µm high on his retina. What is the maximum distance in km at which he can read the 75.0 cm high letters on the side of an airplane? (Assume a 2.0 cm distance between retina and lens.)Ch. 35
- (a) For a converging lens with a focal length of 3.50 cm, find the object distance that will result in an inverted image with an image distance of 5.00 cm. diagram to verify your calculations. Use a ray (b) Is the image virtual or real? (c) What is the magnification?Problem 2: An object with height 0.95 cm is placed a distance 34.5 cm in front of a concave mirror with focal length of 8.75 cm, similar to the image shown. 22md th ICom ViewA gnm The focal-point location is indicated by the small black circle. Part (a) Calculate and enter a value for the distance, in centimeters, between the image and the mirror given the values in problem statemer Numeric : A numeric value is expected and not an expression. d; = %3Dplease answer vv
- In a simplified model of the human eye, the aqueous and vitreous humors and the lens all have a refractive index of 1.40, and all the bending occurs at the cornea, whose vertex is 2.60 cm from the retina. What should be the radius of curvature of the cornea such that the image of an object 40.0 cm from the cornea’s vertex is focused on the retina?A shiny sphere, 30 cm in diameter, is placed in a garden for aesthetic purposes. Calculate the image distance dII of a 6.00-cm-tall squirrel located 46 cm in front of the sphere. Follow the sign convention. (Express your answer to two significant figures.)= 1.0). An object (A) is Assume that a thin lens (r, placed in the left side of lens (d = 45mm) and the image of the object is located in the right side of the lens at position (B) (d' = 90mm). 1) Compute the refraction index of the lens (n2); = -r2 = 40mm) is placed in the air (n 2) If placing another negative thin lens (f2 = -180mm) immediately behind the first lens to create a doublet lens in which the spacing between two lenses is zero (as shown in the right figure), what is the focal length of this doublet? 3) Where is the final image position (C) of the object (A) through this new doublet? (Note: Assuming this doublet lens is a combined thin lens too without considering its thickness).
- An upright object is placed a distance in front of a converging lens equal to twicethe focal length of the lens. On the other side of the lens is a converging mirror of focallength , separated from the lens by a distance ; see diagram below. Find the location, nature, and relative size of the final image, as seen by an eye looking toward the mirrorthrough the lens. Draw the appropriate ray diagramThe person cannot see the objects beyond 15.0 cm distance from the eye. This means, the far point of the person’s eye is 15.0 cm.(a) A 1.00 cm-high object is placed 4.35 cm to the left of a converging lens of focal length 7.85 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. cm---Select--- position height Is the image inverted or upright? upright inverted Is the image real or virtual? real virtual cm (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position? cm distance direction ---Select---