A computer manufacturer is interested in comparing assembly times for two keyboard assembly processes. Process 1 is thestandard process used for several years, and Process 2 is an updated process hoped to bring a decrease in assembly time. Assemblytimes can vary considerably from worker to worker, and the company decides to eliminate this effect by selecting 8 workers atrandom and timing each worker on each assembly process. Half of the workers are chosen at random to use Process 1 first, and therest use Process 2 first. For each worker and each process, the assembly time (in minutes) is recorded, as shown in the table below.WorkerProcess 1Difference(Process 1 - Process 2)Send data to calculator VProcess 2HExplanation18468Check16264293538565204588 35713617 - 1(a) State the null hypothesis Ho and the alternative hypothesis H₁.662362678046348Based on these data, can the company conclude, at the 0.10 level of significance, that the mean assembly time for Process 1exceeds that of Process 2? Answer this question by performing a hypothesis test regarding μ (which is u with a letter "d"μsubscript), the population mean difference in assembly times for the two processes. Assume that this population of differences(Process 1 minus Process 2) is normally distributed.48Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal placesand round your answers as specified. (If necessary, consult a list of formulas.)462μ σрEspaño?BU▷AaCⒸ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibi round your answers as specified. (If necessary, consult a list of formulas.)(a) State the null hypothesis Ho and the alternative hypothesis H₁.Ho :H₁:0(b) Determine the type of test statistic to use.Type of test statistic: (Choose one)(c) Find the value of the test statistic. (Round to three or more decimal places.)(d)Find the critical value at the 0.10 level of significance. (Round to three or more decimalplaces.)(e) At the 0.10 level, can the company conclude that the mean assembly time for Process 1exceeds that of Process 2?O Yes O NoExplanationCheck© 2022 McGraw Hill LLC. All Rights Reserved.

Given, This is a paired 't-test sample size,n= 8 Mean (d̄) =Σd/n = 149/8 = 18.63 standard deviation,Sd =√Σ(d-d̄)2)/n-1) = √1231.8752/(8-1) =13.2658 a) The Null and alternative hypothesis Ho : μd = 0 Ha : μd >0 b) The type of test statistic = 't-test c) Test statistic(t) = (d̄ -μd)/(Sd/√n) = (18.63-0)/(13.2658/√8) = 3.9721 d) degree of freedom(df) = n-1 = 8-1 = 7 level of significance α = 0.10 For a right-tailed test tcritical = = tα/2 ,df= ABS(T.INV(2.2622(α,df)) e) Test criteria : We reject the null hypothesis if test statistic (t) > tcritical Since the test statistic (t) = 3.9721 > tcritical we reject the null hypothesis. Conclusion: Yes at a 0.10 level of significance, we can conclude that the mean assembly time for process 1 exceeds process 2.