A COMPOUND CURVE is composed of three simple curves (CURVE1, CURVE2 & CURVE3). Compute the stationing of PT if the stationing of PC is 6 + 623.56. CURVE1 Radius = 1,157.40 meters CURVE1 Long Chord = 470.80 meters CURVE2 Radius = 550 meters CURVE2 Long Chord = 185.50 meters CURVE3 Radius = 467.87 meters %3D CURVE3 Long Chord = 153.75 meters %3D
A COMPOUND CURVE is composed of three simple curves (CURVE1, CURVE2 & CURVE3). Compute the stationing of PT if the stationing of PC is 6 + 623.56. CURVE1 Radius = 1,157.40 meters CURVE1 Long Chord = 470.80 meters CURVE2 Radius = 550 meters CURVE2 Long Chord = 185.50 meters CURVE3 Radius = 467.87 meters %3D CURVE3 Long Chord = 153.75 meters %3D
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![PROBLEM 1
A COMPOUND CURVE is composed of three simple curves (CURVE1, CURVE2 & CURVE3).
Compute the stationing of PT if the stationing of PC is 6 + 623.56.
CURVE1 Radius = 1,157.40 meters
CURVE1 Long Chord = 470.80 meters
CURVE2 Radius = 550 meters
CURVE2 Long Chord = 185.50 meters
CURVE3 Radius = 467.87 meters
CURVE3 Long Chord = 153.75 meters](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6894b9bb-e80b-463f-a005-39880f5b2045%2F6c1f2902-41d6-4600-9a40-f2117db9ca65%2Fnbkzbsr_processed.png&w=3840&q=75)
Transcribed Image Text:PROBLEM 1
A COMPOUND CURVE is composed of three simple curves (CURVE1, CURVE2 & CURVE3).
Compute the stationing of PT if the stationing of PC is 6 + 623.56.
CURVE1 Radius = 1,157.40 meters
CURVE1 Long Chord = 470.80 meters
CURVE2 Radius = 550 meters
CURVE2 Long Chord = 185.50 meters
CURVE3 Radius = 467.87 meters
CURVE3 Long Chord = 153.75 meters
![PROBLEM 2
A REVERSE CURVE has non-parallel tangents. The common tangent of the reverse curve has a
length of 1,550 meters. The angle of intersection of first curve is 47 degrees and its middle
ordinate is equal to 85.40 meters. If the radius of the first curve is twice as long as the radius of
the second curve, how far is Point PT of he reverse curve from its PC? Use arc basis.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6894b9bb-e80b-463f-a005-39880f5b2045%2F6c1f2902-41d6-4600-9a40-f2117db9ca65%2F0izkpwv_processed.png&w=3840&q=75)
Transcribed Image Text:PROBLEM 2
A REVERSE CURVE has non-parallel tangents. The common tangent of the reverse curve has a
length of 1,550 meters. The angle of intersection of first curve is 47 degrees and its middle
ordinate is equal to 85.40 meters. If the radius of the first curve is twice as long as the radius of
the second curve, how far is Point PT of he reverse curve from its PC? Use arc basis.
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