A simple curve has central angle of 36deg and a degree of curve of 6 deg. Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents. Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the point of curvature and the point of tangency. If the stationing of the point of curvature is at 10+020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 8 deg with the tangent through the P.C. (format: 00+000.00)

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A simple curve has central angle of 36deg and a degree of curve of 6 deg.

Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents.

Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the point of curvature and the point of tangency.
If the stationing of the point of curvature is at 10+020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 8 deg with the tangent through the P.C. (format: 00+000.00)
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With the same problem, use the following formula. R = 191.07m , T = 62.082 , Lc = 118.088m , E = 9.833m , M = 9.352m and L(curve length) = 120.053

Curve length(L) = R x I (Central Angle) x pi/180

Tangent Distance
Middle Ordinate
External Distance
Long Chord
T = R tan (2)
M = R(1-cos(
(→))
E = R(sec() - 1)
Lc = 2R sin /
2
Transcribed Image Text:Tangent Distance Middle Ordinate External Distance Long Chord T = R tan (2) M = R(1-cos( (→)) E = R(sec() - 1) Lc = 2R sin / 2
Degree of Arc basis
Chord Basis
R
R=
1145.916
D
10
sin
Transcribed Image Text:Degree of Arc basis Chord Basis R R= 1145.916 D 10 sin
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