A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of 180° and BC has an azimuth of 230°. The stationing of the point of curvature at A is 50 + 107.00. If the degree of curve of the simple curve is 4°: 1. Compute the length of the long chord from A. 2. Compute the tangent distance AB of the curve. 3. Compute the stationing of point “X" on the curve on which a line passing through the center of the curve makes an angle of 58° with the line AB, intersects the curve at point "X".

A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of 180° and BC has an azimuth of 230°. The stationing of the point of curvature at A is 50 + 107.00. If the degree of curve of the simple curve is 4°: 1. Compute the length of the long chord from A. 2. Compute the tangent distance AB of the curve. 3. Compute the stationing of point “X" on the curve on which a line passing through the center of the curve makes an angle of 58° with the line AB, intersects the curve at point "X".

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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