A composite beam is fabricated by bolting two 3.9-in.-wide by 13-in.-deep timber planks to the sides of a 0.6-in. by 13-in. steel plate. The moduli of elasticity of the timber and the steel are 1540 ksi and 28100 ksi, respectively. The simply supported beam spans a distance of 19 ft and carries two concentrated loads P, which are applied as shown. Assume LAB=LCD= 6 ft, LBC=7 ft, b = 3.9 in., d = 13 in. and t = 0.6 in. (a) Determine the maximum bending stresses 0, 0, produced in the timber planks and the steel plate if P = 2.7 kips. (b) Assume that the allowable bending stresses

A composite beam is fabricated by bolting two 3.9-in.-wide by 13-in.-deep timber planks to the sides of a 0.6-in. by 13-in. steel plate. The moduli of elasticity of the timber and the steel are 1540 ksi and 28100 ksi, respectively. The simply supported beam spans a distance of 19 ft and carries two concentrated loads P, which are applied as shown. Assume LAB=LCD= 6 ft, LBC=7 ft, b = 3.9 in., d = 13 in. and t = 0.6 in. (a) Determine the maximum bending stresses 0, 0, produced in the timber planks and the steel plate if P = 2.7 kips. (b) Assume that the allowable bending stresses

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

a concrete floor slab 100mm thick is cast monotholic with concrete beams 2.0 m on centers. the beams have a span of 4.0m, web width of 259 mm and overall depth of 50 mm. the tensile reinforcement consists of 6-⌀20 mm bars in two rows with 25mm vertical clear spacing. use material strengths f'c=21MPa and fy=415MPa. calculate the ff considering a T-geometry: 1. effective flange width of an interior beam in mm 2. depth of uniform stress block at ultimate stage in mm to the nearest whole number 3. tensile steel strain compatible strain of 0.003
For a composite section attached, derive the equation for Y-bar assuming that the PNA is located in the flange of the steel beam. Hint: Balance the resultant forces through the section. Recall that Y-bar is the distance from the top of the steel flange to the PNA for any location with the PNA below the top of the steel flange.
A laminated beam is composed of four (4) planks, each of 150 mm x 30 mm, glued together to form a section 150 mm x 150 mm. The allowable shear stress in the glue is 850 kPa, the allowable shear stress in the wood is 1050 KPA, and the allowable flexure stress in the wood is 10 MPa. Determine the maximum uniformly distributed load which can be carried by the beam on a 45 m simple span.
Please answer as soon as possible
Note: Read the question carefully and give me both right solutions with clear calculations. Don't copy from already available solutions.
1 Situation 19. A composite beam shown is subjected to a bending moment of 500 kN-m. Determine the maximum flexural stress; 300 VIEW INNOVATIONS 200 200 100 55. Experienced by the steel 56. Experienced by the aluminum A. 0.03 B. 25.24 57. Experienced by the brass A. 25.24 B. 37.86 REVIEW I EW INNOVATIONS Steel, E=200 GPa Aluminum, E=70 GPa Brass, E-105 GPa wwwww C. 48.2 D. 72.11 C. 16.8 C. 16.8 D. 11.21 VIEW INNOVATIONS REVIEW INNOVATIONS REVIEW IS
Required information A composite beam is made by attaching the timber and steel portions shown with bolts of 12-mm diameter spaced longitudinally every 200 mm. The modulus of elasticity is 10 GPa for the wood and 200 GPa for the steel. The vertical shear is 4.4 kN. 12 mm 250 mm 12 mm 150 mm- Determine the average shearing stress in the bolts. (Round the final answers to two decimal places.) The average shearing stress in the bolts is MPa.
The wood beam has an allowable shear stress of tallow = 7 MPa. Determine the maximum shear force V that can be applied to the cross section.
Show complete solution. Thank you
Question 4 A 6 KN force is applied at the free end of a wood (E = 12GPa) beam with dimensions given in Fig. Q4. Neglecting the effect of fillets and stress concentration, determine (a) the maximum compressive stress and its location at section A-A; (b) the maximum shearing stress and its location at section A-A; (c) the deflection at section A-A. 6 kN 300 mm 400 mm ΤΑ 叶 ¡A Fig. Q4 96 mm -- 12 mm 12 mm 48 mm
Find the ultimate moment of resistance for the rectangular section reinforced as shown below. material strengths: Concrete Reinforcement Width of section Reinforcement fcu= 30-MPa fy:= 450-MPa b:= 280 mm d:= 510 mm d':= 50-mm 2 A, 2410-mm A's:= 628-mm 2 b A', Hi As
Asiacell lln. H.W. No.1 For the simply supported solid one way reinforced concrete slab shown in the figure below having a span of (L= 4m), check the following requirements using strength method: a- Slab thickness b- The spacing between reinforcement for main and shrinkage reinforcement c- The actual reinforcement with minimum reinforcement d- Calculate ultimate resisted moment that can be withstand by the slab e- Determine the ultimate uniformly distributed load carried by slab. f = 25 N/mm2 fy=420 N/mm² + 10mm@s00mm shrinkage h=200mm -L=4m- $12mm@200mm main