A common way for two people to settle a frivolous dispute is to play a game of rock-paper-scissors. In this game, each person simultaneously displays a hand signal to indicate a rock, a piece of paper, or a pair of scissors. Rock beats scissors, scissors beats paper, and paper beats rock. If both players select the same hand signal, the game results in a tie. Two roommates, roommate A and roommate B, are expecting company and are arguing over who should have to wash the dishes before the company arrives. Roommate A suggests a game of rock-paper-scissors to settle the dispute. Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 24% of the time, and roommate B chooses rock 85% of the time; roommate A selects paper 12% of the time, and roommate B selects paper 14% of the time; roommate A chooses scissors 64% of the time, and roommate B chooses scissors 1% of the time. (These choices are made randomly and independently of each other.) The probabilities were assigned using the . Define event A as the event that roommate A wins the game and thus does not have to wash the dishes. What is P(A), the probability of event A? P(A) = 0.19 P(A) = 0.22 P(A) = 0.67 P(A) = 0.32 Let event C be the event that the game ends in a tie. What is P(C), the probability of event C? P(C) = 0.23 P(C) = 0.25 P(C) = 0.50 P(C) = 0.32 Define event B as the event that roommate B wins the game and thus does not have to wash the dishes. What is the probability that roommate B wins the game? P(B) = 0.67 P(B) = 0.37 P(B) = 0.58 P(B) = 0.43 What is the complement of event A? AcAc = event B or event C AcAc = event C AcAc = event A or event C AcAc = event B The probability of AcAc is .

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter2: Working With Real Numbers

Section2.7: Problem Solving: Consecutive Integers

Problem 1OE

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A common way for two people to settle a frivolous dispute is to play a game of rock-paper-scissors. In this game, each person simultaneously displays a hand signal to indicate a rock, a piece of paper, or a pair of scissors. Rock beats scissors, scissors beats paper, and paper beats rock. If both players select the same hand signal, the game results in a tie.

Two roommates, roommate A and roommate B, are expecting company and are arguing over who should have to wash the dishes before the company arrives. Roommate A suggests a game of rock-paper-scissors to settle the dispute.

Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 24% of the time, and roommate B chooses rock 85% of the time; roommate A selects paper 12% of the time, and roommate B selects paper 14% of the time; roommate A chooses scissors 64% of the time, and roommate B chooses scissors 1% of the time. (These choices are made randomly and independently of each other.)

The probabilities were assigned using the .

Define event A as the event that roommate A wins the game and thus does not have to wash the dishes.

What is P(A), the probability of event A?

P(A) = 0.19

P(A) = 0.22

P(A) = 0.67

P(A) = 0.32

Let event C be the event that the game ends in a tie.

What is P(C), the probability of event C?

P(C) = 0.23

P(C) = 0.25

P(C) = 0.50

P(C) = 0.32

Define event B as the event that roommate B wins the game and thus does not have to wash the dishes. What is the probability that roommate B wins the game?

P(B) = 0.67

P(B) = 0.37

P(B) = 0.58

P(B) = 0.43

What is the complement of event A?

AcAc = event B or event C

AcAc = event C

AcAc = event A or event C

AcAc = event B

The probability of AcAc is .

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