A column foundation (Figure P6.9) is 3 m × 2 m in plan. Given: D, = 1.5 m, ' = 25°, c' = 70 kN/m². Using Eq. (6.28) and FS = 3, determine the net allowable load [see Eq. (6.24)] the foundation could carry. 1.5 m 1 m FIGURE P6.9 3 mx 2m y = 17 kN/m³ Groundwater level Ysat = 19.5 kN/m³

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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### Problem 6.9

A column foundation (illustrated in Figure P6.9) has a plan dimension of 3 m by 2 m. The given data for the problem is as follows: 

- Depth of foundation, \( D_f = 1.5 \, \text{m} \),
- Angle of internal friction, \( \phi' = 25^\circ \),
- Cohesion, \( c' = 70 \, \text{kN/m}^2 \).

Using Equation (6.28) and a factor of safety (FS) of 3, determine the net allowable load using Equation (6.24) that this foundation can support.

### Diagram Explanation

Figure P6.9 illustrates a cross-sectional view of the foundation. Key elements in the diagram include:

- **Foundation Geometry**: The foundation is rectangular with dimensions of 3 m by 2 m in plan view.
- **Depth Details**: The depth from the foundation's surface level to its bottom is 1.5 m.
- **Soil Layers and Properties**:
  - **Above Groundwater Level**: The soil has a unit weight \( \gamma = 17 \, \text{kN/m}^3 \).
  - **Below Groundwater Level**: The soil is saturated with a unit weight \( \gamma_{\text{sat}} = 19.5 \, \text{kN/m}^3 \).
  
- **Groundwater Level**: The groundwater level is located 1.0 m above the foundation's base.

### Additional Information

- **Equations Mentioned**:
  - Equation (6.28) and (6.24) are referred to, providing guidance on how to calculate the net allowable load using the stated parameters and given conditions.
  
This problem requires a fundamental understanding of geotechnical engineering principles to solve for the net allowable load a foundation can carry, factoring in the soil characteristics and structural requirements.

### FIGURE P6.9

The figure visually supports the explanation, providing a clear representation of the foundation in question, its dimensions, and the surrounding soil conditions.
Transcribed Image Text:### Problem 6.9 A column foundation (illustrated in Figure P6.9) has a plan dimension of 3 m by 2 m. The given data for the problem is as follows: - Depth of foundation, \( D_f = 1.5 \, \text{m} \), - Angle of internal friction, \( \phi' = 25^\circ \), - Cohesion, \( c' = 70 \, \text{kN/m}^2 \). Using Equation (6.28) and a factor of safety (FS) of 3, determine the net allowable load using Equation (6.24) that this foundation can support. ### Diagram Explanation Figure P6.9 illustrates a cross-sectional view of the foundation. Key elements in the diagram include: - **Foundation Geometry**: The foundation is rectangular with dimensions of 3 m by 2 m in plan view. - **Depth Details**: The depth from the foundation's surface level to its bottom is 1.5 m. - **Soil Layers and Properties**: - **Above Groundwater Level**: The soil has a unit weight \( \gamma = 17 \, \text{kN/m}^3 \). - **Below Groundwater Level**: The soil is saturated with a unit weight \( \gamma_{\text{sat}} = 19.5 \, \text{kN/m}^3 \). - **Groundwater Level**: The groundwater level is located 1.0 m above the foundation's base. ### Additional Information - **Equations Mentioned**: - Equation (6.28) and (6.24) are referred to, providing guidance on how to calculate the net allowable load using the stated parameters and given conditions. This problem requires a fundamental understanding of geotechnical engineering principles to solve for the net allowable load a foundation can carry, factoring in the soil characteristics and structural requirements. ### FIGURE P6.9 The figure visually supports the explanation, providing a clear representation of the foundation in question, its dimensions, and the surrounding soil conditions.
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