A college professor claims that the entering class this year appears to be smarter than entering classes from previous years. He tests a random sample of 20 of this year's entering students and finds that their mean IQ score is 117, with standard deviation of 15. The college records indicate that the mean IQ score for entering students from previous years is 113. If we assume that the IQ scores of this year's entering class are normally distributed, is there enough evidence to conclude, at the 0.05 level of significance, that the mean IQ score, u, of this year's class is greater than that of previous years? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H₁. H:0 H₁:0 (b) Determine the type of test statistic to use. (Choose one) ▼ (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three or more decimal places.) (e) Can we conclude, using the 0.05 level of significance, that the mean IQ score H |x X 00 a X S ô 00 ローロ OSO 020 Р O>O S 00 >O

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77°F
Cloudy
V
A college professor claims that the entering class this year appears to be smarter than entering classes from previous years. He tests a random sample of 20 of
this year's entering students and finds that their mean IQ score is 117, with standard deviation of 15. The college records indicate that the mean IQ score for
entering students from previous years is 113. If we assume that the IQ scores of this year's entering class are normally distributed, is there enough evidence to
conclude, at the 0.05 level of significance, that the mean IQ score, u, of this year's class is greater than that of previous years?
Perform a one-tailed test. Then complete the parts below.
Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of
formulas.)
(a) State the null hypothesis Ho and the alternative hypothesis H₁.
0
H :O
H₁ :0
(b) Determine the type of test statistic to use.
(Choose one) Y
(c) Find the value of the test statistic. (Round to three or more decimal places.)
0
(d) Find the p-value. (Round to three or more decimal places.)
0
(e) Can we conclude, using the 0.05 level of significance, that the mean IQ score
E
Explanation
Check
Search
C
3
|x
X
5
#D
O
ロ=ロ OSO
X
S
<D
Ś
P
<Q
010
VO
2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center
Es
9
Transcribed Image Text:77°F Cloudy V A college professor claims that the entering class this year appears to be smarter than entering classes from previous years. He tests a random sample of 20 of this year's entering students and finds that their mean IQ score is 117, with standard deviation of 15. The college records indicate that the mean IQ score for entering students from previous years is 113. If we assume that the IQ scores of this year's entering class are normally distributed, is there enough evidence to conclude, at the 0.05 level of significance, that the mean IQ score, u, of this year's class is greater than that of previous years? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H₁. 0 H :O H₁ :0 (b) Determine the type of test statistic to use. (Choose one) Y (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Can we conclude, using the 0.05 level of significance, that the mean IQ score E Explanation Check Search C 3 |x X 5 #D O ロ=ロ OSO X S <D Ś P <Q 010 VO 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Es 9
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GivenMean(x)=117standard deviation(s)=15sample size(n)=20significance level(α)=0.05

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