A college is trying to determine if there is a significant difference in the mean GMAT score of students from different undergraduate backgrounds who apply to the MBA program.The accompanying GMAT Scores data comes from a sample of students. What conclusion can be reached using ANOVA?E Click the icon to view the GMAT Scores data......Determine the null hypothesis and the alternative hypothesis.Họ:H,:Find the F-test statistic.F=D(Type an integer or decimal rounded to two decimal places as needed.)Find the p-value.p=(Type an integer or decimal rounded to three decimal places as needed.)V the null hypothesis and conclude that theresignificant differences in theThe p-value ismeans of the groups.than the chosen level of significance, 0.05. Therefore,GMAT scores dataGMAT Scores by Undergraduate MajorLiberal ArtsBusinessSciences572562605587573595585582579584572590580563608596576587572577586561603598599605574594606574589584594616585617583580PrintDone

Hypothesis : H0 : μ1 = μ2 = μ3 i.e. There is not significant difference in the mean GMAT score of…

Answered: A college is trying to determine if…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Data were collected from 400 patients in the US about their estrogen level. Out of the 400, 35 patient have abnormal estrogen levels. On a national level, 8 % of patients have abnormal estrogen level. Researchers want to know the sample proportion differs from the national level. 5% is used for significance. Give the Ho and Ha. The appropriate test. Decision rule. Test calculations. Conclusion with comparison to alpha or critical value. I think this is a two tailed test. Use a one sample t- test. I think the null is rejected. t (40-1) = (400-35) / (.05 divided by sqrt 31) This is where I get stuck.
Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a 0.05 significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective? LOADING... Click the icon to view the data table of the poplar weights. No Treatment Fertilizer Irrigation Fertilizer and Irrigation 1.24 0.99 0.09 0.93 0.65 0.94 0.63 1.41 0.41 0.55 0.13 1.06 0.15 0.51 0.88 1.49 1.31 1.01 0.84 Determine the null and alternative hypotheses. H0: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 Exactly two of the population means are equal.Exactly two of the population means are equal. Not all of the population means are equal.Not all of the population means…
According to a recent article about individuals who have credit cards, the mean number of cards per person with credit cards is 4.5. To test this result a random survey of 60 individuals who have credit cards was conducted. The survey only includes the number of credit cards per participant. The results of the survey are attached below. (a) What is the variable of interest in this study? Is it qualitative or quantitative? (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. E Click the icon to view the data from the survey. (a) What is the variable of interest in this study? Is it qualitative or quantitative? The variable of interest is number of credit cards.It is a quantitative variable. (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. State the null and alternative hypotheses. Họ: H = 4.5 < 4.5 H1: H…
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Ten randomly chosen participants in a Math Training Program took a pretest and a posttest. Test at 0.05 level of significance whether the variance of the posttest scores is significantly different from the variance of the pretest scores. Use the data the following data. [pretest: 5, 6,7,7,7,8,8,9,9,10] [posttest: 6,7,9,8,7,913,10,11,6]
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Is narcissism a more common personality trait today than it was a few decades ago? It is known that the mean population score on the Narcissistic Personality Inventory (NPI) for students attending University of South Alabama around 20 years ago was μ= 15 (Twenge, 2010). Interested in the narcissism levels of students in the year 2020, a researcher administers the NPI to a random sample of 25 University of Alabama sophomores this Spring term. The mean NPI score from the researcher’s sample of sophomores is M = 16.5, with s = 3.4. 1. Write the null and alternative hypotheses in symbols. Possible symbols for your answer: H0, H1, μ, M, σ. 2. Calculate the standard error. 3. Find the critical value for the test statistic, assuming alpha = .05 (Use largest [i.e., most conservative] value if exact value not given in the chart) a) 2.064 b) 1.96 c) 1.98 d) 2.000
Since an instant replay system for tennis was introduced at a major tournament, men challenged 1413 referee calls, with the result that 426 of the calls were overturned. Women challenged 742 referee calls, and 228 of the calls were overturned. Use a 0.05 significance level to test the claim that men and women have equal success in challenging calls. Identify the test statistic. z= ? (Round to two decimal places as needed.) Part 3 Identify the P-value. P-value= ? (Round to three decimal places as needed.) Part 4 What is the conclusion based on the hypothesis test? The P-value is ▼ greater than or less than the significance level of α=0.05, so ▼ fail to reject or reject the null hypothesis. There ▼ is not sufficient or is sufficient evidence to warrant rejection of the claim that women and men have equal success in challenging calls. Part 5 b. Test the claim by constructing an appropriate confidence interval. The 95% confidence…
use ms excel, thank you!
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
Describe a study in which you can use both nonparametric and parametric statistics. A researcher has participants expecting to receive either painful or mild electrical shocks during a study wait in a quarter-full waiting room with other participants. He then measures whether they choose to sit next to other participants or if they sit far away on their own. What is the best test to run for this study and why?
A statistician changes her level of significance from .001 to .05. What impact will this change have on her risk of making a Type I and Type II error? Is the change in the level of significance a good decision? Why or why not?

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