A college is trying to determine if there is a significant difference in the mean GMAT score of students from different undergraduate backgrounds who apply to the MBA program.The accompanying GMAT Scores data comes from a sample of students. What conclusion can be reached using ANOVA?E Click the icon to view the GMAT Scores data......Determine the null hypothesis and the alternative hypothesis.Họ:H,:Find the F-test statistic.F=D(Type an integer or decimal rounded to two decimal places as needed.)Find the p-value.p=(Type an integer or decimal rounded to three decimal places as needed.)V the null hypothesis and conclude that theresignificant differences in theThe p-value ismeans of the groups.than the chosen level of significance, 0.05. Therefore,GMAT scores dataGMAT Scores by Undergraduate MajorLiberal ArtsBusinessSciences572562605587573595585582579584572590580563608596576587572577586561603598599605574594606574589584594616585617583580PrintDone

Hypothesis : H0 : μ1 = μ2 = μ3 i.e. There is not significant difference in the mean GMAT score of…

Answered: A college is trying to determine if…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Below indicate whether the appropriate test would be an independent t-test, dependent t-test, One-way ANOVA, or z-test. . A statistics professor wants to know if students who turn their homework in on time get higher exam grades than students who do not turn their homework in on time.
During the 2010 MLB seasons, the home team won 1,269 games and the away team won 1,371 games. What is the test statistic to compare the observed data versus a 50/50 outcome? Round to two decimal places.
What type of statistical test is this? Is the test significant? In order to determine where the main mean differences lie, the researcher would also need to conduct a _______?
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Data were collected from 400 patients in the US about their estrogen level. Out of the 400, 35 patient have abnormal estrogen levels. On a national level, 8 % of patients have abnormal estrogen level. Researchers want to know the sample proportion differs from the national level. 5% is used for significance. Give the Ho and Ha. The appropriate test. Decision rule. Test calculations. Conclusion with comparison to alpha or critical value. I think this is a two tailed test. Use a one sample t- test. I think the null is rejected. t (40-1) = (400-35) / (.05 divided by sqrt 31) This is where I get stuck.
Q: Using the data (provided below this question) apply ANOVA to determine if the mean response for value for the dollar is the same for different types of cell phones. Use a 5% significance level if the problem doesn’t give an alpha. Note: Please only provide the t stat, p-value, and critical value, no need to explain the whole process. Gender Carrier Type Usage Signal strength Value for the Dollar Customer Service M AT&T Smart High 5 4 4 M AT&T Smart High 5 4 2 M AT&T Smart Average 4 4 4 M AT&T Smart Very high 2 3 3 M AT&T Smart Very high 5 5 2 M AT&T Smart Very high 4 3 5 M AT&T Smart Very high 3 4 4 F AT&T Smart Very high 3 2 3 F AT&T Smart Very high 4 3 4 M AT&T Smart Very high 3 3 1 M Other Smart Average 1 2 4 M Sprint Smart Very high 3 5 4 M Sprint Smart Very high 3 5 3 F Sprint Smart Average 2 5 4 F Sprint Smart Average 3 5 4 M Verizon Smart Average 4 3 3 F Verizon Smart Very high 4 3 2 M Verizon…
Low-fat or low-carb? Are low-fat diets or low-carb diets more effective for weight loss? A sample of 77 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 4.7 kilograms with a sample standard deviation of 7.16 kilograms. A second sample of 79 subjects went on a low-fat diet. Their sample mean weight loss was 2.6 kilograms with a standard deviation of 5.90 kilograms. Can you conclude that the mean weight loss differs between the two diets? Let 4, denote the mean weight lost on the low-carb diet and u, denote the mean weight lost on the low-fat diet. Use the a = 0.01 level and the TI-84 Plus calculator. Compute the -value. Round the answer to four decimal places. Determine whether to reject H0 State a conclusion
Seven acute schizophrenics and 10 chronic schizophrenics have been measured on a clarity of thinking scale. The mean for the acute sample was 52, with s = 12, and the mean for the chronic sample was 44, with s = 11. Perform a pooled-variance t test with alpha = .05 (two-tailed), and state your statistical conclusion.
You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.71. Thus you are performing a right-tailed test. Your sample data produce the test statistic z = 3.006. Find the p-value accurate to 4 decimal places. p-value =
A clinical researcher performs a clinical trial on 12 patients to determine whether a drug treatment has an effect on serum glucose. The sample mean glucose of the patients before and after the treatment are summarized in the following table. The sample standard deviation of the differences was 6. Sample mean glucose (mg/dL) Before treatment 114 After treatment 108 What type of hypothesis test should be performed?Select: Left-tailed z-test Unpaired t-test Two-tailed z-test Paired t-test What is the test statistic? What is the number of degrees of freedom? Does sufficient evidence exist to support the claim that the drug treatment has an effect on serum glucose at the α=0.05 significance level? Select: _____Yes OR _____No
A data set includes the counts of chocolate chips from three different types of Chips Ahoy cookies. The accompanying StatCrunch display shows results from analysis of variance used with those three types of cookies. Use a 0.05 significance level to test the claim that the three different types of cookies have the same mean number of chocolate chips. ANOVA table Source ns on Viewer Error Total DF SS MS F-Stat P-value 2 1235.5500 617.77500 62.2790 <0.0001 77 763.80000 9.9194805 79 1999.3500 Ho: H₁ H₂ H3 Determine the alternative hypothesis. H₁: At least one of the means is different from the others Determine the test statistic. The test statistic is 62.28. (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.)
A study of seat belt users and nonusers yielded the randomly selected sample data summarized in the accompanying table. Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke are less concerned about their health and safety and are therefore less inclined to wear seat belts, Is this theory supported by the sample data? BB Click the icon to view the data table. Determine the null and alternative hypotheses. O A. Ho: The amount of smoking is dependent upon seat belt use. H₁: The amount of smoking is not dependent upon seat belt use. O B. Ho: Heavy smokers are not less likely than non-smokers to wear a seat belt. H₁: Heavy smokers are less likely than non-smokers to wear a seat belt. OC, Ho: Heavy smokers are less likely than non-smokers to wear a seat belt. H₁: Heavy smokers are not less likely than non-smokers to wear a seat belt. O D. Ho: The amount of smoking is independent of seat belt…

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