A clinical trial was conducted using a new method designed to increase the probability of conceiving a boy. As of this writing, 286 babies were born to parents using the new method, and 238 of them were boys. Use a 0.05 significance level to test the claim that the new method is effective in increasing the likelihood that a baby will be a boy. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. Question content area bottom Part 1 Which of the following is the hypothesis test to be conducted? A. H0: p<0.5 H1: p=0.5 B. H0: p>0.5 H1: p=0.5 C. H0: p≠0.5 H1: p=0.5 D. H0: p=0.5 H1: p≠0.5 E. H0: p=0.5 H1: p>0.5 F. H0: p=0.5 H1: p<0.5 Part 2 What is the test statistic? z=enter your response here (Round to two decimal places as needed.) Part 3 What is the P-value? P-value=enter your response here (Round to four decimal places as needed.) Part 4 What is the conclusion on the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, α. B. Fail to reject the null hypothesis because the P-value is greater than the significance level, α. C. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α. Part 5 What is the final conclusion? A. There is not sufficient evidence to warrant rejection of the claim that the new method is effective in increasing the likelihood that a baby will be a boy. B. There is sufficient evidence to support the claim that the new method is effective in increasing the likelihood that a baby will be a boy. C. There is sufficient evidence to warrant rejection of the claim that the new method is effective in increasing the likelihood that a baby will be a boy. D. There is not sufficient evidence to support the claim that the new method is effective in increasing the likelihood that a baby will be a boy.

A clinical trial was conducted using a new method designed to increase the probability of conceiving a boy. As of this writing, 286 babies were born to parents using the new method, and 238 of them were boys. Use a 0.05 significance level to test the claim that the new method is effective in increasing the likelihood that a baby will be a boy. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. Question content area bottom Part 1 Which of the following is the hypothesis test to be conducted? A. H0: p<0.5 H1: p=0.5 B. H0: p>0.5 H1: p=0.5 C. H0: p≠0.5 H1: p=0.5 D. H0: p=0.5 H1: p≠0.5 E. H0: p=0.5 H1: p>0.5 F. H0: p=0.5 H1: p<0.5 Part 2 What is the test statistic? z=enter your response here (Round to two decimal places as needed.) Part 3 What is the P-value? P-value=enter your response here (Round to four decimal places as needed.) Part 4 What is the conclusion on the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, α. B. Fail to reject the null hypothesis because the P-value is greater than the significance level, α. C. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α. Part 5 What is the final conclusion? A. There is not sufficient evidence to warrant rejection of the claim that the new method is effective in increasing the likelihood that a baby will be a boy. B. There is sufficient evidence to support the claim that the new method is effective in increasing the likelihood that a baby will be a boy. C. There is sufficient evidence to warrant rejection of the claim that the new method is effective in increasing the likelihood that a baby will be a boy. D. There is not sufficient evidence to support the claim that the new method is effective in increasing the likelihood that a baby will be a boy.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

A clinical trial was conducted using a new method designed to increase the probability of conceiving a boy. As of this writing, 286 babies were born to parents using the new method, and 238 of them were boys. Use a 0.05 significance level to test the claim that the new method is effective in increasing the likelihood that a baby will be a boy. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
Question content area bottom
Part 1
Which of the following is the hypothesis test to be conducted?
A.
H0: p<0.5
H1: p=0.5
B.
H0: p>0.5
H1: p=0.5
C.
H0: p≠0.5
H1: p=0.5
D.
H0: p=0.5
H1: p≠0.5
E.
H0: p=0.5
H1: p>0.5
F.
H0: p=0.5
H1: p<0.5
Part 2
What is the test statistic?
z=enter your response here
(Round to two decimal places as needed.)
Part 3
What is the P-value?
P-value=enter your response here
(Round to four decimal places as needed.)
Part 4
What is the conclusion on the null hypothesis?
A.
Reject the null hypothesis because the P-value is greater than the significance level, α.
B.
Fail to reject the null hypothesis because the P-value is greater than the significance level, α.
C.
Reject the null hypothesis because the P-value is less than or equal to the significance level, α.
D.
Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α.
Part 5
What is the final conclusion?
A.
There is not sufficient evidence to warrant rejection of the claim that the new method is effective in increasing the likelihood that a baby will be a boy.
B.
There is sufficient evidence to support the claim that the new method is effective in increasing the likelihood that a baby will be a boy.
C.
There is sufficient evidence to warrant rejection of the claim that the new method is effective in increasing the likelihood that a baby will be a boy.
D.
There is not sufficient evidence to support the claim that the new method is effective in increasing the likelihood that a baby will be a boy.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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