A clinical trial was conducted using a new method designed to increase the probability of conceiving a girl. As of this​ writing, 956 babies were born to parents using the new​ method, and 873 of them were girls. Use a 0.01 significance level to test the claim that the new method is effective in increasing the likelihood that a baby will be a girl. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution. 1. What is the test statistic? 2. What is the p-value?

Q: An executive believes that no more than 80% of the company’s employees take all of their vacation…

A:

Q: Suppose 247 subjects are treated with a drug that is used to treat pain and 55 of them developed…

A: Solution: Let X be the number of subjects developed nausea and n be the number of subjects are…

Q: In one study of smokers who tried to quit smoking with nicotine patch​ therapy, 39 were smoking one…

A: Given: x=39 n=39+30=69

Q: In a study of 822 randomly selected medical malpractice​ lawsuits, it was found that 499 of them…

A: given data claim : p > 0.5n = 822x = 499α = 0.01p^ = xn = 499822 = 0.60706

Q: study of pregnant women and their ability to correctly predict the sex of their​ baby, 57 of the…

A: From the given information we conduct z test for Proportion.

Q: Which of the following is the hypothesis test to be conducted? OA. Ho: p=0.5 H₁: p<0.5 OC. Ho: p<0.5…

A:

Q: What are the null and alternative​ hypotheses? Identify the test statistic. Identify the​ P-value.…

A: For vinyl gloves, sample size n1= 276, sample proportion = 57% = 0.57 For latex gloves, sample size…

Q: A basketball player claims that the success of his shots is more than 70%. If this player scored 152…

A: From the data given: x=152 n=200 p^=xn=152200=0.76   Null and Alternate Hypothesis: H0: p=0.7 Ha:…

Q: Research done in 2013 found that only 48% of all the site users reported getting their news about…

A: The question is about hypothesis testing and confidence interval.Given :Population proportion of all…

Q: Consider a sample of 5353 football​ games, where 3232 of them were won by the home team. Use a…

A: Solution: From the given information, the claim is that the home team wins is greater than 0.5.…

Q: Consider a sample of 54 football​ games, where 28 of them were won by the home team. Use a 0.01…

A: From the provided information, Sample size (n) = 54 out of which 28 were won by the home team.…

Q: In a study of 780 randomly selected medical malpractice lawsuits, it was found that 473 of them were…

A:

Q: car company believes that the percentage of residents in city ABC that owns a vehicle is 60% or…

A: Given information- Population proportion, p = 0.60 Sample size, n = 250 Significance level, α = 0.1…

Q: A researcher drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 203…

A: The observed frequencies for the outcomes of 1, 2, 3, 4, 5 and 6 are 27, 29, 40, 47, 26 and 34…

Q: A clinical trial was conducted using a new method designed to increase the probability of conceiving…

A: State the appropriate hypothesis: The investigator is specially interested to test the claim that…

Q: An institute conducted a clinical trial of its method for gender selection. The results showed that…

A: The total number of babies , n = 319. The number of favorable cases  , x = 176. Significance level ,…

Q: Suppose 239 subjects are treated with a drug that is used to treat pain and 53 of them developed…

A: The objective of this question is to test the claim that more than 20% of users develop nausea after…

Q: random sample of 841 births included 433 boys. Use a 0.05 significance level to test the claim that…

A: Solution

Q: A think tank claims that at most 53% of consumers believe that animals should be allowed into…

A:

Q: Do chickens lay more eggs when soothing music is played in the coop? To find out, researchers played…

A: The objective is to define the appropriate hypothesis test to conclude if the chickens lay more eggs…

Q: In a program designed to help patients stop​ smoking, 235 patients were given sustained​ care, and…

A: Solution: Given information: n=235 Sample size  p^=0.809  Sample proportion  p=0.80 Population…

Q: According to a recent poll, 74 out of 250 randomly selected U.S. adults interviewed said hey would…

A: Given: Let n represents the number of randomly selected U.S adults(n=250). Let X represents the…

Q: A marketing survey invoives product recognition in New York and California. Of 585 New Yorkers…

A: The sample proportions are

Q: A random sample of 866 births included 429 boys. Use a 0.05 significance level to test the claim…

A: Given that  Sample size n =866 Favorable cases x =429 Sample proportion p^=x/n  =429/866 =0.4954

Q: A study was conducted to determine the effectiveness of Omega 3 as prevention for heartburn. 35 out…

A: Given, x1 = 35 n1 = 41 x2 = 41 n2 = 82     To find, Test the claim that Omega3 has an effect on…

Q: Consider a drug testing company that provides a test for marijuana usage. Among 299 tested​…

A: given data  n = 299 x = 29 claim : p &lt; 0.10 we have to find null and alternative hypothesis.

Q: 1. What is the test statistic? 2. What is the p-value? 3. Conclusion about the null hypothesis?

A: The hypotheses can be constructed as: Null hypothesis: H0: p = 0.70 Alternative hypothesis: Ha: p ≠…

Q: Consider a sample of 47 football games, where 32 of them were won by the home team. Use a 0.10…

A:

Q: In a study of 816 randomly selected medical malpractice lawsuits, it was found that 500 of them were…

A: Sample size n =816Favorable cases x =500significance level()=0.01Sample proportion()==0.6127

Q: in a study of 801 randomly selected medical malpractice​ lawsuits, it was found that 495 of them…

A: When the value of sample size is large (30 or more than 30) we use the z test as our test statistic.…

Q: In a study of 811 randomly selected medical malpractice​ lawsuits, it was found that 473 of them…

A:

Q: A USA Today survey basis for report that 57% of gun owners favor stricter gun laws. Assume the group…

A: We have to find decision.

Q: study of 820 randomly selected medical malpractice​ lawsuits, it was found that 513 of them were…

A: Given : Claim : Most medical malpractice lawsuits are dropped or dismissed.

Q: A hardware company has claimed that at least 35% of their purchases were conducted by international…

A: As per guidelines, we will only answer first question.  Null hypothesis: H0: P≥0.35   Alternative…

Q: n a recent poll of 755 randomly selected​ adults, 585 said that it is morally wrong to not report…

A: State the hypotheses.

Q: Consider a drug testing company that provides a test for marijuana usage. Among   307 tested​…

A: We have given that  Sample size=n=307 Favorable=X=27 p0=10%=0.10 Significance level=alpha=0.10

Q: A national survey conducted in 2011 among a simple random sample of 1507 adults shows that 56% of…

A: p^=0.56n=1507

Q: Salaries for teachers in a particular elementary school district are normally distributed with a…

A:

Q: In a recent court case it was found that during a period of 11 years 873 people were selected for…

A: Given : Sample size = n = 873 p = 0.799 p^ = 0.42 level of significance = 0.01

Q: a study of 822 randomly selected medical malpractice lawsuits, it was found that 518 of them were…

A:

Q: Student loan debt is the only form of consumer debt that has grown since the peak of consumer debt…

A: a. The given mean is $20,500, and standard deviation is $4,500.

Q: ​Historically, the percentage of residents of a certain country who support stricter gun control…

A: Given Data

Q: ional Budget Office reports that 36% of federal civilian employees have a bachelor’s degree or…

A: 1. The null hypothesis will be based on the previous that 36% of federal civilian employees have a…

Q: In a programn a program designed to help patients stop​ smoking, 219 patients were given sustained​…

A: Given,   Sample size = 219 Sample proportion = 0.84

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.