A clever engineer designs a "sprong" that obeys the force law F₂ = -q(x-x)³, where is the equilibrium position of the end of the sprong and q is the sprong constant. For simplicity, we'll let x=0 m. Then F₂ = −qx³
A clever engineer designs a "sprong" that obeys the force law F₂ = -q(x-x)³, where is the equilibrium position of the end of the sprong and q is the sprong constant. For simplicity, we'll let x=0 m. Then F₂ = −qx³
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A clever engineer designs a "sprong" that obeys the
force law F₂ = -q(x - x)³, where x is the
equilibrium position of the end of the sprong and q
is the sprong constant. For simplicity, we'll let
xe =0 m. Then F₂ =-qx³

Transcribed Image Text:Part A
What are the units of q?
N
N/m
N/m²
ⒸN/m³
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Correct
Part B
Find an expression for the potential energy of a stretched or compressed sprong.
Express your answer in terms of the variables g and z.
U(z)= qr¹
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Correct
Part C
A sprong-loaded toy gun shoots a 24 g plastic ball. What is the launch speed if the sprong constant is 4.6x10 N/m³ and the sprong is compressed 13 cm? Assume the barrel is frictionless.
Express your answer with the appropriate unite.
- 32
m
S
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