A circular ring of radius R, as in figure, is charged with a charge Q for half of its length and -Q for the other half. Imagine the ring on a plane. Calculate the eletric field at some point, P, located at some distance d from the center of the ring and along the axis perpendicular to the plane containing the ring and passing through the center, O, of the ring. +
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- A 2.25 kg ball hangs by a 17 cm long thread between two oppositely charged parallel plates as shown below. The plates create a uniform horizontal E-field of 294 N/C. As a result, the ball has moved 8 cm from the vertical. (NOTE: Calling the E-field "uniform" means it's the exact same everywhere between the plates.) 17 cm F 8 cm Determine the charge (include polarity) of the ball. q= Determine the tension in the thread. F₁ = Determine the polarity of each plate. You will not receive credit until you have correctly selected the polarities of both plates. left plate positive right plate negativeA single proton is accelerated in a uniform E-field (directed eastward) at 3.2x10^8 m/s^2. Find the magnitude of the field and direction of the acceleration.An electron traveling horizontally enters a region where a uniform electric field is directed upward. What is the direction of the force exerted on the electron once it has entered the field? electron O downward O upward O out of the page, toward the reader O to the left O to the right
- Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.60R from the disk (see Figure (a)). Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.60 (see Figure (b)). Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what part will you decrease the electric field magnitude at P? Number i Units (a) (b)The rod In the figure is uniformly charged with lambda= +3 × 10^−3 C/m. Find the electric field at point P. R= 20 cm.A negatively charged particle is moving at an angle with a component of velocity in the +y-direction when it enters a region with a uniform electric field pointing in the +y-direction. Describe (or sketch) the motion of the charge after entering the electric field. How do you know this is what will happen (what direction is the acceleration)?
- A ring of radius R that lies in the xy plane carries a positive charge Q uniformly distributed over its lerigth. A particle of mass m that carries a negative charge of magnitude q is at the center of the ring. (a) Show that if x << R, the electric field along the axis of the ring is proportional to z. (b) Find the force on the particle of mass m as a function of z. (c) Show that if m is given a small displacement in the x direction, it will perform simple harmonic motion. Calculate the period of that motionCalculate the value of an electric field at a point 5 m away from two positive electric charges of 49.3 µC and 20 µC that are located 10 m apart in vacuum. Provide your answer in Sl units.