Calculate the total force on a charge of 6.00 µC placed at the center of curvature. A line of positive charge is formed into a semicircle of radius \( R = 65.0 \, \text{cm} \), as shown in the figure below. The charge per unit length along the semicircle is given by the expression \( \lambda = \lambda_0 \cos(\theta) \). The total charge on the semicircle is \( 10.0 \, \mu \text{C} \). Calculate the total force on a charge of \( 6.00 \, \mu \text{C} \) placed at the center of curvature.**Diagram Explanation:**The diagram shows:- A semicircle with radius \( R \).- A coordinate system with the origin at point \( P \), the center of curvature.- An angle \( \theta \) indicating the position along the semicircle.- An arrow along the \( y \)-axis indicating the direction of force measurement.**Interactive Elements:**There are input fields for:- Entering the magnitude of the force in newtons (N).- Selecting the direction of the force.

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Answered: A line of positive charge is formed…

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