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In this problem, you have two charges q1=1µC and q2=-1.46µC (µC stands for "micro-Coulomb). You are asked to determine the value of the electric force at point P. q2 is located a distance of 6.53m to the left of P, and q1 is located a further 2.38m to the left of q2. If the net electric field at point P points to the left, then your value should be negative. If the value of the net electric field at point P is oriented to the right, then you value should be positive.
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- Two test charges are located in the x–y plane. If q1=−4.550 nC and is located at x1=0.00 m, y1=0.9200 m, and the second test charge has magnitude of q2=4.200 nC and is located at x2=1.500 m, y2=0.450 m, calculate the x and y components, Ex and Ey, of the electric field E in component form at the origin, (0,0). The Coulomb force constant is 1/(4??0)=8.99×109 N·m2/ C2.Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q₁ = -24.00 nC and 92 = 8.00 nC. Express your answer in vector form.) E E = N/C -4 -2 y (cm) 92 2 91 4 x (cm)part A) A dipole is formed by separating a +200 nC and -200 nC charge a distance of 30 mm. Determine the magnitude of the electric field at a distance of 12 meters measured perpendicularly from the midpoint between the charges. Express your answer in N/C. part B) The electric field at point P is 5.9 x 1020 N/C @ 241o. What is the angle of the force experienced by a electron if it is placed at point P. Express your answer in degrees.