The figure below shows a small, charged bead, with a charge of q=+42.0 nC, that moves a distance of d = 0.177 m from point Ato point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right.E9A+i(a) What is the magnitude (in N) and direction of the electric force on the bead?magnitudeNdirection(c) What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the beadand all its surroundings.)PEBPE =AB+---Select---(b) What is the work (in J) done on the bead by the electric force as it moves from A to B?J=J(d) What is the potential difference (in V) between A and B?VB - VAV

Answered: Image /qna-images/answer/80c02619-5a0b-4372-b1dc-8c31749cfbbe.jpg

The figure below shows a small, charged bead, with a charge of q = +42.0 nC, that moves a distance of d = 0.177 m from point A to point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right. E A (a) What is the magnitude (in N) and direction of the electric force on the bead? magnitude N direction PEB ---Select--- (b) What is the work (in J) done on the bead by the electric force as it moves from A to B? - PE = B (c) What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.) J (d) What is the potential difference (in V) between A and B? VB-VA =

The figure below shows a small, charged bead, with a charge of q = +42.0 nC, that moves a distance of d = 0.177 m from point A to point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right. E A (a) What is the magnitude (in N) and direction of the electric force on the bead? magnitude N direction PEB ---Select--- (b) What is the work (in J) done on the bead by the electric force as it moves from A to B? - PE = B (c) What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.) J (d) What is the potential difference (in V) between A and B? VB-VA =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A particle having a negative charge of 1.0 x 106 C experiences an upward force of 9 N when placed at…

A: part 1 charge q= -1.0* 10^-6 force=9N part 2 charge q= 1.0* 10^-6 force=9N

Q: A small plastic bead has a mass of 3.94 g and a charge of -18.2 µC. It levitates, motionless, when…

Q: pls help me with the given question and make sure your answer is right A charge q1�1 = 5.00 nC is…

A: The charge at the origin, Q1=5.00 nC The charge at x=4cm on the x-axis is Q2=-3.00 nC The charge at…

Q: Positive charge q1=2.5μC and two negative charges q2=-1.5μC and q3= -3.55 μC are placed on corners…

Q: A rod 12.0 cm long is uniformly charged and has a total charge of -24.0 µC. Determine the magnitude…

A: Solution -Electric field on the point of the axis =Length of the rod = lDistance of the nearer end…

Q: Part A Which of the following is not true about the electric field generated by a charge? O Positive…

A: (a) Electric Field line are directed radially outward from a positive charge i.e. it points away…

Q: A small glass bead has been charged to +40.0 nC. A small metal ball bearing 1.00 cm above the bead…

A: charge on small glass bead (q1) = 40 nC distance between ball bearing and bead (d) = 1 cm = 0.01 m…

Q: Two identical balls of 35.9 g are suspended from threads of length 1.14 m and carry equal charges as…

A: The mass of the two identical balls is given as, m=m1=m2=35.9 g The length of the wire suspended is…

Q: small compared to the distance between them. Each object acquires each object experiences an…

A: using coulomb's law, the electrostatic force between two charges is given by F = kq1q2/r2. where k…

Q: A rod 12.0 cm long is uniformly charged and has a total charge of -20.0 μC. Determine the magnitude…

A: Solution -Electric field on the point of the axis =Length of the rod = lDistance of the nearer end…

Q: 3. Two identical small, charged spheres are at a certain distance apart, and each one initially…

Q: A DNA molecule can be seen as a charged line with a linear charge density of λ. Suppose the DNA…

A: Solution attached in the photo

Q: Find the magnitude and direction of the net electric field at point A. The two particles in the…

Q: A point charge q = +4 µC is at the center of a sphere of radius 0.2 m. 1) Find the surface area of…

A: The surface area of the sphere can be calculated using the formula: Surface area = 4πr2 where r is…

Q: A Part (a) At the point where the proton is exiting from the gap between the plates, its path has…

A: Given details are magnitude of the electric field, E= 4.2 x 105 N/Cspeed of proton, vp = 1.8 x 107…

Q: Three charges are at the comers of an isosceles triangle as shown in the figure (Eigure 1). The 5.00…

A: Given three charges are at a corner of an isosceles triangle as shown in the figure. The charges…

Q: The magnitude of the force between two stationary, charged dust particles is 24.0 µN. If the…

A: Given value--- The magnitude of the force between two stationary, charged dust particles is 24.0…

Q: A uniform electric field exists in the region between two oppositely charged parallel plates 1.68 cm…

A: Given data: Distance between the plates, d=1.68 cm = 0.0168 m Time interval, t=1.48×10-6 s Mass of…

Q: The drawing shows two situations in which charges are placed on the x and y axes. They are all…

A: Electric field The Electric field, also known as electric field intensity is the measure of the…

Q: A +7.5 nC charge is placed at point A as shown on the graph below. (let K = 9X10° N-m²/C²) y(m 5 4 3…

A: the distance AB is provided by (AB)2=42+32(AB)2=25AB=5m Explanation We…

Q: Part A What must the charge (sign and magnitude) of a particle of mass 1.40 g be for it to remain…

Q: A positively charged particle Q1 = 25 nC is held fixed at the origin. A negatively charged particle…

Q: Four point charges have the same magnitude of 2.47 10-12 C and are fixed to the corners of a square…

Q: A charge q1=−2q is at the origin, and a charge q2=+q is on the x-axis at x=a, where a>0. A.) Find…

Q: A point charge gives rise to an electric field with magnitude 1 N/C at a distance of 2 m. If the…

A: Let a point charge q gives rise to a field of 1 N/C. Electric field is given by, E=q4πε0r2 It is…

Q: Calculate the magnitude of the electric field at one corner of a square 1.52 m on a side if the…

Q: Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads…

Q: Part a) A +6 nC charge is located 3.6 meters to the right of a +5 nC charge. Determine the magnitude…

A: a) Given data The magnitude of the first charge is given as q1 = 6 nC. The magnitude of the second…

Q: A point charge is placed at each corner of a square with side length a. All charges have magnitude…

A: Given, Point charges are each corner of square of side a

Q: he magnitude of the electric field due to this particle at a point 0.200 mm directly above it.…

A: Given:- The particle of the charge q = -2.75 nC The distance d = 0.2 m, this particle at a point…

Q: Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads…

Q: Three positive point charges (A, B, and C) lie along the same line and are separated by a distance…

A: The electric field at A due to the charge at B is: E→1 = kqd2 = (9×109)(0.961×10-6)0.1652 =…

Q: Two identical balls of 29.5 g are suspended from threads of length 1.1 m and carry equal charges as…

Q: A small glass bead has been charged to + 10.0 nC. A small metal ball bearing 3.00 cm above the bead…

A: The final answer is - 1.5 * 10-7 C . Here force is attractive , given one charge is positive . So…

Q: What are the magnitude and direction of the force exerted on a 4.41 µC charge by a 184 N/C electric…

Q: A rod 12.0 cm long is uniformly charged and has a total charge of -24.0 μC. Determine the magnitude…

A: Given: The length of the rod, L=12.0 cm=0.12 m The uniform charge, Q=-24.0 μC=-24.0×10-6 C The…

Q: A charged particle A exerts a force of 2.40 ?N to the right on charged particle B when the particles…

Q: Consider the following. (a) Red blood cells often become charged and can be treate point charges.…

Q: A small plastic bead has a mass of 3.68 g and a charge of -16.6 µC. It levitates, motionless, when…

Q: Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads…

Q: A positive charge of magnitude Q1 = 0.55 nC is located at the origin. A negative charge Q2 = -6.5 nC…

Q: The figure below shows a small, charged sphere, with a charge of q = +42.0 nC, that moves a distance…

Q: 60.0 magnitude. direction 0.500 mm (a) Red blood cells often become charged and can be treated as…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

The figure below shows a small, charged bead, with a charge of q
=
+42.0 nC, that moves a distance of d = 0.177 m from point A
to point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right.
E
9
A
+
i
(a) What is the magnitude (in N) and direction of the electric force on the bead?
magnitude
N
direction
(c) What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead
and all its surroundings.)
PEB
PE =
A
B
+
---Select---
(b) What is the work (in J) done on the bead by the electric force as it moves from A to B?
J
=
J
(d) What is the potential difference (in V) between A and B?
VB - VA
V

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: GIVEN

VIEW

Step 2: calculation of magnitude and direction of electric force

VIEW

Step 3: calculation of work done on bead by electric force

VIEW

Step 4: Calculation of change of the electric potential energy

VIEW

Step 5: calculation of potential energy

VIEW

Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 6 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Below is a depiction of one type of adjustable dial. This dial is essentially a thin rod with a charged sphere on the end, seated inside an electric field. The sphere between these plates has a charge of −2.3 µC and the thin rod can be approximated as a string with tension 0.350 N, at an angle of 15° as shown below. a) What is the mass of the charged ball? g b) What is the magnitude of the electric field between the plates?N/C
1) Charge for q2 = 6.00 x 10^-12 C. Determine the magnitude of the electrical field. Express the answer in N/C form. 2) Using a new value of 7.4 nC for q2, determine the charge needed at point P so that the electric field due to all four charges is zero at point z. Express your answer in nC and include a negative sign if the charge is negative. Please use what I have provided for the questions.
The figure below shows a small, charged sphere, with a charge of q = +41.0 nC, that moves a distance of d = 0.162 m from point A to point B in the presence of a uniform electric field E of magnitude 290 N/C, pointing right. 9 A E d (a) What is the magnitude (in N) and direction of the electric force on the sphere? N magnitude direction = B + --Select--- (b) What is the work (in J) done on the sphere by the electric force as it moves from A to B? J (c) What is the change of the electric potential energy (in J) as the sphere moves from A to B? (The system consists of the sphere and all its surroundings.) PEB - PEA J (d) What is the potential difference (in V) between A and B? VB-VA = V
A point charge gives rise to an electric field with magnitude 4 N/C at a distance of 9 m. If the distance is increased to 45 m, then what will be the new magnitude of the electric field? N/C
A positively charged particle Q1=+25 nC is held fixed at the origin. A second charged Q2 of mass m=8.5 ug is floating a distance d=25 cm above charge Q1. The net force on Q2 is equal to zero. You may assume this system is close to the surface of the Earth. b. Calculate the magnitude of q2 in units of nanocoulumbs.
Two point charges are separated by 25.0 cm (see (Figure 1)). Assume that g₁ = -8.00 nC and 92 = -12.5 nC. Figure 10.0 cm 9 25.0 cm 10.0 cm 1 of 1 Find the net electric field these charges produce at point A. Express your answer in newtons per coulomb. E= Part B Find the net electric field these charges produce at point B. Express your answer in newtons per coulomb. E = N/C N/C
Two m = 5.8 g point charges on 1.0-m-long threads repel each other after being charged to q = 80 nC, as shown in the figure. (Figure 1) Figure 1.0 m m + 9 00 1.0 m +m 9 1 of 1 Part A What is the angle 0? You can assume that is a small angle. Express your answer to two significant figures and include the appropriate units. μ 0 = 4.21 Submit μÅ Ω % À X Previous Answers Request Answer ? X Incorrect; Try Again; 7 attempts remaining
A-3.00 nC point charge is at the origin, and a second-5.50 mC point charge is on the z-axis at z-0.800 m. ▾ Part D Find the net electric force that the two charges would exart on an electron placed at point on the z-axis at 0.200 m Express your answer with the appropriate units. Enter positive value if the force is in the positive z-direction and negative value if the force is in the negative z-direction. Correct answer is shown. Your answer 724.5 was either rounded differently or used a different number of significant figures than required for this part F₁ = Value Submit ▾ Part E F₂ = Submit Part F μÀ Find the net electric force that the two charges would exart on an electron placed at point on the z-axis at a = 1.20 m Express your answer with the appropriate units. Enter positive value if the force is in the positive z-direction and negative value if the force is in the negative z-direction. F₂ Request Answer Submit BÀ Value Request Answer À Units Value Find the net electric force…
= + 4.0 nc located at the origin of a consider an electric dipole consisting of a point charge q1 coordinate system and a second charge q2 = - 4.0 nc located at (0.10 m, 0 m). 0.15 m 0.05 m 0.05 m q1 q2 a) find the electric field at points (0.05 ,0 m) and (0.05 m, 0.15 m) due to this dipole. b) what is the electric force on a 2.0 nc charge placed at these points. c) use the far-field approximation to find the electric field e at a point 1.5 m away from the dipole along the perpendicular bisector at coordinates (0.05 m, 1.5 m)?
In the picture below, the rod is positively charged. Electrically speaking, water is a "polar molecule"; each water molecule can be imagined as a negative charge (the oxygen end) and a positive charge (the hydrogen end), each of approximate magnitude 2e, separated by an approximate distance of 2 x10-1" m. a) Explain how a charged rod can exert an electric force on water molecules that have zero net charge. Include a picture of a typical water molecule in the stream of water adjacent to the rod, showing its orientation relative to the rod. b) If the charge of the rod is +32 nC and that charge is located approximately 2.0 cm from a water molecule in the stream, what is the maximum possible net electric force that the rod could exert on the molecule?
Two small beads having positive charges q₁ = 29q and q2 = q are fixed at the opposite ends of a horizontal insulating rod of length d = 1.50 m. The bead with charge q₁ is at the origin. As shown in the figure below, a third small, charged bead is free to slide on the rod. 91 + d 92 (a) At what position x is the third bead in equilibrium? x = 0.87868 -0.879 m (b) Can the equilibrium be stable? OYes, if the third bead has a positive charge O Yes, if the third bead has a negative charge O No
A positive charge of magnitude Q1 = 0.45 nC is located at the origin. A negative charge Q2 = -6.5 nC is located on the positive x-axis at x = 4.5 cm from the origin. The point P is located y = 5.5 cm above charge Q2. Part (a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. Part (b) Calculate the y-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. Part (c) Calculate the y-component of the electric field at point P due to the Charge Q2. Write your answer in units of N/C. Part (d) Calculate the y-component of the electric field at point P due to both charges. Write your answer in units of N/C. Part (e) Calculate the magnitude of the electric field at point P due to both charges. Write your answer in units of N/C. Part (f) Calculate the angle in degrees of the electric field at point P relative to the positive x-axis.