A circular footing with a 1.5 m diameter is to be constructed 1.22 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters: Angle of Friction = 250 Nc = 24.1 Nq = 13.1 Ny = 9.1 Cohesion = 48 kN/m2 Unit weight of soil = 20.12 kN/m2 The groundwater table is at a great depth and its effect can be ignored. Determine the following: a) Ultimate bearing Capacity of the soil

A circular footing with a 1.5 m diameter is to be constructed 1.22 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters: Angle of Friction = 250 Nc = 24.1 Nq = 13.1 Ny = 9.1 Cohesion = 48 kN/m2 Unit weight of soil = 20.12 kN/m2 The groundwater table is at a great depth and its effect can be ignored. Determine the following: a) Ultimate bearing Capacity of the soil

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A rectangular footing (4.31 x 4.07 m.) is placed 1.2 m. below the ground surface. The soil arrangement is composed of sand (ground) for the first 5.52 meters and followed by clay for the next 5.91 meters. The force acting on the footing is 10,163 kN. Determine the settlement of the consolidating layer in mm. Assume a 2V:1H pressure diagram. Unit weight of sand = 16.6 kN/m3. Clay has the following properties: Unit weight = 18 kN/m3, Void ratio = 82, Liquid limit = 44. Round off to two decimal places.
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15 The soil arrangement shown carries 1.88-meter square footing with a column load of 596 kN. Properties of sand: Above water table = 17.04 kN/m3, Below water table = 18.19 kN/m3. Properties of clay: 17.10 kN/m3, Cc = 0.383, void ratio = 0.65. Use H1 = 6 m., H2 = 7 m., H3 = 5 m., Df = 1 m. Determine the settlement of the normally consolidated clay in mm. Round off to three decimal places.
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