A circuit consists of three resistors connected in parallel to a 24.0-V battery. Given that R₁ = 225 , R₂ = 155 and R3 = 135 Q find the total current supplied by the battery. Answer Units: [A] R₁ 3 H R₂ ww R3

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### Parallel Resistors and Current in a Circuit

**Problem Statement:**

A circuit consists of three resistors connected in parallel to a 24.0-V battery. Given that \( R_1 = 225 \, \Omega \), \( R_2 = 155 \, \Omega \), and \( R_3 = 135 \, \Omega \), find the total current supplied by the battery.

**Answer Units:** \([A]\)

**Diagram:**

The accompanying circuit diagram illustrates three resistors \( R_1 \), \( R_2 \), and \( R_3 \), connected in parallel. The resistors are linked to a battery with an electromotive force (ε) of 24.0 V. Currents \( I_1 \), \( I_2 \), and \( I_3 \) flow through resistors \( R_1 \), \( R_2 \), and \( R_3 \) respectively, while the total current \( I \) flows from the battery through the parallel network of resistors.

**Explanation:**

1. **Resistors in Parallel:**
   When resistors are connected in parallel, the voltage across each resistor is the same. The total current \( I \) supplied by the battery is the sum of the currents flowing through each resistor.

2. **Calculating Individual Currents:**
   Using Ohm's law \( V = IR \):
   - The current \( I_1 \) through resistor \( R_1 \):
     \[
     I_1 = \frac{V}{R_1} = \frac{24.0 \, \text{V}}{225 \, \Omega} = 0.107 \, \text{A}
     \]
   - The current \( I_2 \) through resistor \( R_2 \):
     \[
     I_2 = \frac{V}{R_2} = \frac{24.0 \, \text{V}}{155 \, \Omega} = 0.155 \, \text{A}
     \]
   - The current \( I_3 \) through resistor \( R_3 \):
     \[
     I_3 = \frac{V}{R_3} = \frac{24.0 \, \text{V}}{135 \, \Omega} = 0.178 \, \text
Transcribed Image Text:### Parallel Resistors and Current in a Circuit **Problem Statement:** A circuit consists of three resistors connected in parallel to a 24.0-V battery. Given that \( R_1 = 225 \, \Omega \), \( R_2 = 155 \, \Omega \), and \( R_3 = 135 \, \Omega \), find the total current supplied by the battery. **Answer Units:** \([A]\) **Diagram:** The accompanying circuit diagram illustrates three resistors \( R_1 \), \( R_2 \), and \( R_3 \), connected in parallel. The resistors are linked to a battery with an electromotive force (ε) of 24.0 V. Currents \( I_1 \), \( I_2 \), and \( I_3 \) flow through resistors \( R_1 \), \( R_2 \), and \( R_3 \) respectively, while the total current \( I \) flows from the battery through the parallel network of resistors. **Explanation:** 1. **Resistors in Parallel:** When resistors are connected in parallel, the voltage across each resistor is the same. The total current \( I \) supplied by the battery is the sum of the currents flowing through each resistor. 2. **Calculating Individual Currents:** Using Ohm's law \( V = IR \): - The current \( I_1 \) through resistor \( R_1 \): \[ I_1 = \frac{V}{R_1} = \frac{24.0 \, \text{V}}{225 \, \Omega} = 0.107 \, \text{A} \] - The current \( I_2 \) through resistor \( R_2 \): \[ I_2 = \frac{V}{R_2} = \frac{24.0 \, \text{V}}{155 \, \Omega} = 0.155 \, \text{A} \] - The current \( I_3 \) through resistor \( R_3 \): \[ I_3 = \frac{V}{R_3} = \frac{24.0 \, \text{V}}{135 \, \Omega} = 0.178 \, \text
**(Continued from the previous question) Find the current through \( R_2 \).**

---

This task is likely part of a larger problem related to electrical circuits. In such scenarios, the previous question might have provided information such as the values of resistances, voltages, and possibly a circuit diagram. Please ensure you have reviewed the preceding content to understand the full context of the problem.

### Explanation:
To find the current through \( R_2 \), you would typically use Ohm's Law, Kirchhoff's Voltage Law (KVL), or Kirchhoff's Current Law (KCL) depending on the given information and the circuit configuration. 

1. **Ohm's Law**: \( V = IR \)
   - \( V \) is the voltage across the resistor,
   - \( I \) is the current through the resistor,
   - \( R \) is the resistance.

2. **Kirchhoff's Voltage Law (KVL)**: The sum of all voltages around a closed loop is zero.
3. **Kirchhoff's Current Law (KCL)**: The sum of currents entering a junction equals the sum of currents leaving the junction.

### Example Steps to Solve:
1. Identify the total voltage in the circuit and any given resistance values.
2. Use KVL or KCL to write down the equations for the circuit.
3. Solve the equations to find the current through \( R_2 \).

Ensure you have the necessary information from the previous question to apply these laws correctly.
Transcribed Image Text:**(Continued from the previous question) Find the current through \( R_2 \).** --- This task is likely part of a larger problem related to electrical circuits. In such scenarios, the previous question might have provided information such as the values of resistances, voltages, and possibly a circuit diagram. Please ensure you have reviewed the preceding content to understand the full context of the problem. ### Explanation: To find the current through \( R_2 \), you would typically use Ohm's Law, Kirchhoff's Voltage Law (KVL), or Kirchhoff's Current Law (KCL) depending on the given information and the circuit configuration. 1. **Ohm's Law**: \( V = IR \) - \( V \) is the voltage across the resistor, - \( I \) is the current through the resistor, - \( R \) is the resistance. 2. **Kirchhoff's Voltage Law (KVL)**: The sum of all voltages around a closed loop is zero. 3. **Kirchhoff's Current Law (KCL)**: The sum of currents entering a junction equals the sum of currents leaving the junction. ### Example Steps to Solve: 1. Identify the total voltage in the circuit and any given resistance values. 2. Use KVL or KCL to write down the equations for the circuit. 3. Solve the equations to find the current through \( R_2 \). Ensure you have the necessary information from the previous question to apply these laws correctly.
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