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A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.

A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...
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A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.
Transcribed Image Text:A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.
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