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A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.

A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 57P
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A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.
Transcribed Image Text:A chemist titrates 50.0 ml of a 0.1190M aniline (C,H,NH,) solution with 0.6692M HCI solution at 25 °C. Calculate the pH at equivalence. The p K, aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.
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