A chemist has 70.0 mL of a 16.0 M solution of HCl. He dilutes the acid with water to make ithave a molarity of 10.0 M. What is the new volume of the acid? Equations- M = mol of solute /L of solution for molarity M 1 (V 1 ) = M 2 (V 2 ) for dilution
A chemist has 70.0 mL of a 16.0 M solution of HCl. He dilutes the acid with water to make ithave a molarity of 10.0 M. What is the new volume of the acid? Equations- M = mol of solute /L of solution for molarity M 1 (V 1 ) = M 2 (V 2 ) for dilution
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 52QRT: You want to prepare a 1.0 mol/kg solution of ethyleneglycol, C2H4(OH)2, in water. Calculate the mass...
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A chemist has 70.0 mL of a 16.0 M solution of HCl. He dilutes the acid with water to make it
have a molarity of 10.0 M. What is the new volume of the acid?
Equations- M = mol of solute /L of solution for molarity
M 1 (V 1 ) = M 2 (V 2 ) for dilution
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