A chemist designs a galvanic cell that uses these two half-reactions: half-reaction N₂(g)+4H₂O(1)+4e → N₂H₂(aq)+4OH¯ (aq) Cu²+ (aq) + Cut (aq) Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode. standard reduction potential E = -1.16 V "red E "red = +0.153 V ローロ 10₁ % 0.²

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### Galvanic Cell Design and Analysis

#### A chemist designs a galvanic cell that uses these two half-reactions:

| half-reaction                           | standard reduction potential       |
|-----------------------------------------|-----------------------------------|
| N₂(g) + 4H₂O(l) + 4e⁻ → N₂H₄(aq) + 4OH⁻(aq) | E₀_{red} = -1.16 V                |
| Cu²⁺(aq) + e⁻ → Cu⁺(aq)                | E₀_{red} = +0.153 V               |

---

### Answer the following questions about this cell.

1. **Write a balanced equation for the half-reaction that happens at the cathode.**
   \[ \boxed{} \]

2. **Write a balanced equation for the half-reaction that happens at the anode.**
   \[ \boxed{} \]

3. **Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written.**
   \[ \boxed{} \]

4. **Do you have enough information to calculate the cell voltage under standard conditions?**
   - [ ] Yes
   - [ ] No

5. **If you said it was possible to calculate the cell voltage, do so and enter your answer here. Be sure your answer has the correct number of significant digits.**
   \[ \boxed{} \, \text{V} \]

### Explanation of Components:
- **Cathode Half-Reaction:** This is where the reduction occurs (gain of electrons).
- **Anode Half-Reaction:** This is where the oxidation occurs (loss of electrons).
- **Overall Cell Reaction:** The sum of the anode and cathode half-reactions, ensuring spontaneity based on standard reduction potentials.
- **Cell Voltage:** The potential difference between the cathode and anode, calculated using standard reduction potentials.

---

In the table above, standard reduction potentials (E₀_{red}) are provided for the given half-reactions. Use these values to determine the overall cell voltage and the spontaneity of the galvanic cell reaction.
Transcribed Image Text:### Galvanic Cell Design and Analysis #### A chemist designs a galvanic cell that uses these two half-reactions: | half-reaction | standard reduction potential | |-----------------------------------------|-----------------------------------| | N₂(g) + 4H₂O(l) + 4e⁻ → N₂H₄(aq) + 4OH⁻(aq) | E₀_{red} = -1.16 V | | Cu²⁺(aq) + e⁻ → Cu⁺(aq) | E₀_{red} = +0.153 V | --- ### Answer the following questions about this cell. 1. **Write a balanced equation for the half-reaction that happens at the cathode.** \[ \boxed{} \] 2. **Write a balanced equation for the half-reaction that happens at the anode.** \[ \boxed{} \] 3. **Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written.** \[ \boxed{} \] 4. **Do you have enough information to calculate the cell voltage under standard conditions?** - [ ] Yes - [ ] No 5. **If you said it was possible to calculate the cell voltage, do so and enter your answer here. Be sure your answer has the correct number of significant digits.** \[ \boxed{} \, \text{V} \] ### Explanation of Components: - **Cathode Half-Reaction:** This is where the reduction occurs (gain of electrons). - **Anode Half-Reaction:** This is where the oxidation occurs (loss of electrons). - **Overall Cell Reaction:** The sum of the anode and cathode half-reactions, ensuring spontaneity based on standard reduction potentials. - **Cell Voltage:** The potential difference between the cathode and anode, calculated using standard reduction potentials. --- In the table above, standard reduction potentials (E₀_{red}) are provided for the given half-reactions. Use these values to determine the overall cell voltage and the spontaneity of the galvanic cell reaction.
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