esc1Introduction to hypothesis tests for the population mean using...p 2: Enter the test statistic.(Round to 3 decimal places.)Step 4: Enter the p-value.(Round to 3 decimal places.)Step 3: Shade the area represented bythe p-value.(c) Based on your answer to part (b), choose what the manager can conclude, at the 0.05 level of significance.Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there isenough evidence to conclude that the mean wait time is now greater than 9 minutes.Explanation2O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is notenough evidence to conclude that the mean wait is now greater than 9 minutes.O Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidenceto conclude that the mean wait time is now greater than 9 minutes.CheckO Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enoughevidence to conclude that the mean wait time is now greater than 9 minutes.#3$40.3-*0.2-%50.1-^6MacBook Pro4&C7* 008-X9© 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | AccessibilityAyishatuCSEspañol? 圖 □ 图日 □C escA chain of restaurants has historically had a mean wait time of 9 minutes for its customers. Recently, the restaurant added several very popular dishes back totheir menu. Due to this, the manager suspects the wait time, μ, has increased. He takes a random sample of 44 customers. The mean wait time for the sampleis 9.6 minutes. Assume the population standard deviation for the wait times is known to be 3.3 minutes.Can the manager conclude that the mean wait time is now greater than 9 minutes? Perform a hypothesis test, using the 0.05 level of significance.(a) State the null hypothesis Ho and the alternative hypothesis H₁.Ho: DH₁: 0(b) Perform a Z-test and find the p-value.Here is some information to help you with your Z-test.• The value of the test statistic is given byStandard Normal DistributionStep 1: Select one-tailed or two-tailed..O One-tailedO Two-tailedExplanationHCheckOOMacBook ProEspañol?CÙD19AsⒸ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibil

There are two parts of statistical inference. These are testing of hypothesis and estimation. In…

Answered: A chain of restaurants has historically…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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due to the increasing price of apartments each year, houston chronicle reported that rent of 1 bed 1 bath apartments in houston and suburbs is $1200 with standard deviation of $500. suppose claire decided to take 20 different random samples from the different houston areas. in how many samples would she expect to get the price to be more that $1100?
Kira recently switched her primary doctor to one specializing in caring for elderly patients. On her new doctor's website, it says that the mean systolic blood pressure among elderly females is 120 millimeters of mercury (mmHg). Kira believes the value is actually higher. She bases her belief on a recently reported study of 11 randomly selected, elderly females. The sample mean systolic blood pressure was 124mmHg, and the sample standard deviation was 24mmHg . Assume that the systolic blood pressures of elderly females are approximately normally distributed. Based on the study, at the 0.10 level of significance, can it be concluded that μ , the population mean systolic blood pressure among elderly females, is greater than 120 mmHg ? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H0 and the…
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 150 students in evening classes and finds that they have a mean test score of 88.8. He knows the population standard deviation for the evening classes to be 8.4 points. A random sample of 250 students from morning classes results in a mean test score of 89.9. He knows the population standard deviation for the morning classes to be 5.4 points. Test his claim with a 99% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 3 of 3 : Draw a conclusion and interpret the decision.
It seems these days that college graduates who are employed full-time work more than 40-hour weeks. Data are available that can help us decide if this is true. A survey was recently sent to a group of adults selected at random. There were 15 respondents who were college graduates employed full-time. The mean number of hours worked per week by these 15 respondents was 43 hours, with a standard deviation of 8 hours. Assume that the population of hours worked per week by college graduates employed full-time is normally distributed with mean μ. Can we conclude that μ is greater than 40 hours? Use the 0.05 level of significance. State the null hypothesis H0 and the alternative hypothesis H1 Find the t-test df & Solve the t-test value Find the critical value Can we conclude, at the 0.05 level of significance, that the mean number of hours worked per week by college graduates is greater than 40 hours? Yes or No?
Suppose that, in 1995, the weight of 16-year old males in the United States was normally distributed with a mean of 148 lbs and standard deviation equal to 19 lbs. Suppose that Roger, a public health researcher, believes that the popularity of video and computer gaming has made teenagers less active, and predicts that 16-year old males today weigh more than 16-year old males did in 1995. To test the theory, he chooses a random sample of 50 16-year old males and records their weights. The average weight of the sample is 153 lbs. Roger uses a z-test to test the hypothesis that the average weight of 16-year old males has increased. He calculates the z-statistic as 1.86 standard deviations above the mean. Use this standard normal z-distribution table to calculate the P-value of this statistic. Give your answer as a decimal rounded to four places. P-value:
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 76.8. He knows the population standard deviation for the evening classes to be 7.2 points. A random sample of 200 students from morning classes results in a mean test score of 77.8. He knows the population standard deviation for the morning classes to be 1.9 points. Test his claim with a 90% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
Fast Auto Service provides oil and lube service for cars. It is known that the mean time taken for oil and lube service at this garage is 15 minutes per car and the standard deviation is 2.4 minutes. The management wants to promote the business by guaranteeing a maximum waiting time for its customers. If a customer's car is not serviced within that period, the customer will receive a 50% discount on the charges. The company wants to limit this discount to at most 3% of the customers. What should the maximum guaranteed waiting time be? Assume that the times taken for oil and lube service for all cars have a normal distribution.Round your answer to the nearest minute.
Suppose that you randomly survey death records for people born in 1900 in Louisiana and compared the life span of two different ethnicities. Of the 109 individuals sampled from ethnicity 1, the mean life span was 45.5 years with a standard deviation of 18.2 years. Of the 105 individuals sampled from ethnicity 2, the mean life span was 44.9 years with a standard deviation of 11.4 years. Conduct a hypothesis test with a 10% level of significance to see if the mean life spans in Louisiana were the same for the two ethnicities. Step 1: State the null and alternative hypotheses. Ho: µ1 – µ2 =v Ha:H1 – µ2 # v (So we will be performing a two-tailed ♥ test.)
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 76.8. He knows the population standard deviation for the evening classes to be 7.2 points. A random sample of 200 students from morning classes results in a mean test score of 77.8. He knows the population standard deviation for the morning classes to be 1.9 points. Test his claim with a 90% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1__μ2
According to the historical data, the life expectancy in Belgium is less than the life expectancy in the United States. A new study has been made to see whether this has changed. Records of 260 individuals from Belgium who died recently are selected at random. The 260 individuals lived a mean of 78.4 years with a standard deviation of 8.8 years. Records of 285 individuals from the United States who died recently are selected at random and independently. The 285 Individuals lived a mean of 76.5 years with a standard deviation of 7.4 years. Assume that the population standard deviations of lifetimes in these two countries can be estimated by the sample standard deviations, as the samples used were quite large. Construct a 95% confidence interval for ₁-₂, the difference between the life expectancy μ₁ in Belgium and the life expectancy μ₂ in the United States. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three…
Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 37 randomly selected people who train in groups, and finds that they run a mean of 47.7 miles per week. Assume that the population standard deviation for group runners is known to be 3.3 miles per week. She also interviews a random sample of 49 people who train on their own and finds that they run a mean of 49.4 miles per week. Assume that the population standard deviation for people who run by themselves is 4.4 miles per week. Test the claim at the 0.10 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
Suppose Professor Alpha and Professor Omega each teach Introductory Biology. You need to decide which professor to take the class from and have just completed your Introductory Statistics course. Records obtained from past students indicate that students in Professor Alpha's class have a mean score of 80% with a standard deviation of 5%, while past students in Professor Omega's Class have a mean score of 80% with a standard deviation of 10%. Decide which instructor to take for Introductory Biology using a statistical argument.

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