A certain type of piping system uses deformable rings to clamp pipes onto fittings. A crimping tool that isused to make these connections is shown here. Find the internal forces and bending moment in the lowerjaw at section s-s, located midway between pins B and E, when a force of F = 63 lb is applied to thehandles as shown. Be sure to follow the sign conventions for internal loadings when entering your answers.2013 Michael SwanbomCCcrimpringBY NC SAabсdh₁h₂●statb-d-FValues for dimensions on the figure are given in the following table. Note the figure may not be to scale.Variable Value1.96 in7 in1.29 in14.3 in5 in9 inHINT: The assume the ring has no frictionThe internal axial load at section s-s in the lower jaw is A =The internal shear load at section s-s in the lower jaw is V =The internal bending moment at section s-s in the lower jaw is M =ولاIFlb.lb.in-lb.

Answered: Image /qna-images/answer/49c1fcd5-bacc-46ed-b09f-629df61c75e2.jpg

A certain type of piping system uses deformable rings to clamp pipes onto fittings. A crimping tool that is used to make these connections is shown here. Find the internal forces and bending moment in the lower jaw at section s-s, located midway between pins B and E, when a force of F= 63 lb is applied to the handles as shown. Be sure to follow the sign conventions for internal loadings when entering your answers. 2013 Michael Swanbom C180 BY NC SA crimp ring IF Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a b с d h₁ h₂ a ●E 1.96 in 7 in 1.29 in 14.3 in 5 in 9 in b→ -d. с HINT: The assume the ring has no friction The internal axial load at section s-s in the lower jaw is A - The internal shear load at section s-s in the lower jaw is V- The internal bending moment at section s-s in the lower jaw is M - lb. lb. in-lb.

A certain type of piping system uses deformable rings to clamp pipes onto fittings. A crimping tool that is used to make these connections is shown here. Find the internal forces and bending moment in the lower jaw at section s-s, located midway between pins B and E, when a force of F= 63 lb is applied to the handles as shown. Be sure to follow the sign conventions for internal loadings when entering your answers. 2013 Michael Swanbom C180 BY NC SA crimp ring IF Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a b с d h₁ h₂ a ●E 1.96 in 7 in 1.29 in 14.3 in 5 in 9 in b→ -d. с HINT: The assume the ring has no friction The internal axial load at section s-s in the lower jaw is A - The internal shear load at section s-s in the lower jaw is V- The internal bending moment at section s-s in the lower jaw is M - lb. lb. in-lb.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: Attention !!!! Please clarify this . When they go to calculate both the normal stress of the bolt…

A: Step 1: Step 2: Step 3: Step 4:

Q: Determine the force in member BC of the loaded truss. The force is positive if in tension, negative…

A: Consider upward & horizontal forward force as (+)ve and downward force as (-)ve. Assume…

Q: Problem 1: The steel pipe has an inner diameter of 2.75 in and an outer diameter of 3 in. The pipe…

Q: Use the method of sections to determine the forces in members BD, CD, and CE of the Warren truss…

Q: In the assembly shown, rod AB is made of steel (E = 200 GPa) and has a diameter D = 50 mm. Rod BC is…

A: Given data: STEEL…

Q: Q6. As shown in the image below, the rigid member ACB (with negligible thickness) is subjected to…

A: Given:- F1=340N F2=360N α=34°β=57°

Q: ired information E: This is a multi-part question. Once e given figure, the bent rod ABEF is mm…

Q: Question 2 The vertical shaft and the pulleys keyed to it in Figure Q2 may be regarded as…

Q: Warm-up/Example "0" We will work through this problem together at the completion of lecture. The…

A: Given data: The beam is fixed at A

Q: Please solve in Handwritten format with free body diagram. Don't use chatgpt.

A: Step 1:

Q: A gear reduction unit uses the countershaft shown in the figure. Gear A receives power from another…

A: Pressure angle, ϕ=20oTransmitted force, FA=11400 NDiameter of shaft, dshaft=52 mm

Q: Looking for handwritten solution with diagram.

A: Let's break down the solution step by step:Calculate the Total Load (P_total):The triangular…

Q: Clamps like the one shown are commonly used in woodworking applications. This clamp has the…

A: Solution: Given Data: t=49 mmP=115 kPaw=115000 Pa×0.049 m=5635 N/mμs=0.4

Q: A shaft with a diameter d = 25 mm must transfer a torque of 23 Nm by using a key joint. The key has…

Q: The ultimate tensile strength (Su) of the material if the Yield strength (Sy) is 0.6 of Ultimate…

A: DefinitionS-N Diagram:The S-N diagram can be used to design components that are subject to cycle…

Q: 8. The following assembly is supported by a pin at A and frictionless a roller at B in the given…

Q: i) Find the "x" and "y" components of the reaction force at A. Ax A₂ Ay = ii) Find the "x" and "y"…

A: According to the given dataConsidering the free body diagram AC and BCDE We need to find theReaction…

Q: Solve the problem shown below. Each answer is worth equal credit. Show all necessary steps of your…

A: The value of applied force is

Q: The overhang beam is supported by a pin at point A and a roller at point B. A distributed load is…

Q: A mild steel bracket as shown in figure below, is subjected to a pull of 6000 N acting at 45° to its…

Q: Please draw a FBD only for the circled yellow part known as a rubber base plate :) I don’t want the…

Q: The nail cutter consists of the handle and the two cutting blades (Eigure 1) Figure 6 mm 6 mm -36 mm…

A: According to the given data F=6 N We need to find Force on the fingernail by the cutter

Q: Onv Problems 9-29 to 9-32 F 9-29 to 9-32 A steel bar of thickness h is welded to a vertical support…

Q: Suppose the load in the figure below is 2 kN. Further suppose that the distance between the load and…

A: Given : P= 2kN The distance between load and centroid is 1.3 m The horizontal distance between bolt…

Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

100%

A certain type of piping system uses deformable rings to clamp pipes onto fittings. A crimping tool that is
used to make these connections is shown here. Find the internal forces and bending moment in the lower
jaw at section s-s, located midway between pins B and E, when a force of F = 63 lb is applied to the
handles as shown. Be sure to follow the sign conventions for internal loadings when entering your answers.
2013 Michael Swanbom
CC
crimp
ring
BY NC SA
a
b
с
d
h₁
h₂
●
stat
b
-d-
F
Values for dimensions on the figure are given in the following table. Note the figure may not be to scale.
Variable Value
1.96 in
7 in
1.29 in
14.3 in
5 in
9 in
HINT: The assume the ring has no friction
The internal axial load at section s-s in the lower jaw is A =
The internal shear load at section s-s in the lower jaw is V =
The internal bending moment at section s-s in the lower jaw is M =
ولا
IF
lb.
lb.
in-lb.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Two parts of a machine, both made from steel, are held together by 7 equally-spaced M6 x 1.0 grade 8.8 bolts that are uniformly tightened to provide a total initial clamping force of 60 kN. What wrench torque is required to set the preload on these bolts? Assume a torque factor of 0.18 in your calculations. Express your answer in units of newton meters to a resolution of 0.1 N-m.
Problem 5: At times in design, you would like to ensure that failure occurs in a specific part. For instance, in watch designs many components are stacked on top of one another due to the small space requirements. In this case if failure must occur, it is best that it happens in a gear that is easy to access. Using the maximum shear stress theory and only the stresses related to bending, determine the safety factors of the teeth on gears A, B, and C below. Each tooth can be assumed to be a rectangular cantilever beam with a point force at the end, the force can be determined using Torque = F x r. 0000 Gear B Gear C Gear A Torque on Shaft Gear Radius Tooth Length Tooth Height Tooth Thickness Gear A 10 N-mm 8.0 mm 1.5 mm 1.5 mm 0.5 mm Gear B 8 N-mm 3.0 mm 2.0 mm 1.5 mm 0.5 mm Gear C 6 N-mm 5.0 mm 1.5 mm 2.0 mm 0.8 mm Gear D Gear D 30 N-mm 10.0 mm 1.5 mm 1.5 mm Solve Material: Steel E =200 GPa Sy = 250 MPa
Hi, our topic here is about METHOD OF SECTIONS kindly help me find the correct solution to this problem. Asap! Thank you!
The 200 x 200 x 1,250-mm oak [E-12 GPa] block (2) shown is reinforced by bolting two 5 x 200 x 1,250 mm steel [E - 200 GPa] plates (1) to opposite sides of the block. A concentrated load of 300 kN is applied to a rigid cap. Assume P-300 kN, L-1.25 m. Determine (a) the normal stresses in the steel plates (1) and the oak block (2). (b) the shortening of the block when the load is applied. B (1) Answers: A₁- A₂- i Part 2 Calculate the cross-sectional area of each steel plate, A₁, and the cross-sectional area of the oak block, Az. i Save for Later P CL (2) C Answer: F₂/F₁- CL Save for Later CL (1) mm² mm² Derive a compatibility equation using force-deformation relationships substituted into a geometry-of-deformation relationship. Express the compatibility equation here as the ratio of the force in the oak block, F₂, to the force in each steel plate, F₁. Attempts: 0 of 1 used Submit Answer Attempts: 0 of 1 used Submit Answer
- once answered Correctly will UPVOTE!!
How do i find the force of Ay and Fy. Can this probelm be solved woth method of joints. Also what is the C or T, x and y components and the load of each member. Also when you put the answer can you put it like it is on the image please.
5.1 Please help. Provide Free Body Diagram, labeled with appropriate quantities to better understand. Also solve. Thank you.
Help!!! Please answer Correctly !! Clearly solved Please !!!!!!!!
A crank loaded by a force F 1300 N that causes twisting and bending of a 20 mm -in-diameter shaft. (a) Draw separate free-body diagrams of the shaft AB and the arm BC, and compute the values of all forces, moments, and torques that act. Label the directions of the coordinate axes on these diagrams. BC and indicate where these act. (b) Locate a stress element on the top surface of the shaft at A, and calculate all the stress components that act upon this element. (c) Determine the maximum normal and shear stresses at A.
The lifting arm shown below needs to lift a weight of 4 (N). Assuming the links are weightless, determine the magnitude of the force being applied by the pin at B on the lifting arm to the nearest hundredth of a newton. 10Em) 6icm- 150 A Servo Horn Arm 4 (W) 'Servo
solve all