A certain string can withstand a maximum tension of 40 N without breaking. A child ties a 0.37 kg stone to one end and, holding the other end, whirls the stone in a vertical circle of radius 0.91 m, slowly increasing the speed until the string breaks. (a) Where is the stone on its path when the string breaks? (b) What is the speed of the stone as the string breaks?

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A: Given: Mass of ball = m Length of string = l Radius of circular path = R

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A: Solution

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A: Given,m = 504 kgr1 = 10.0 mr2 = 15.0 mvA = 19.8 ms

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A: The solution for this question has been given below...

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A: GivenInitial velocity (u) = 140 m/sequation of height h(t) = 140 t - 16t2

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.